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3 years ago

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Brigitte is shorter than 5 feet. (Brigitte's height=h). Help please

2 answers:

Liono4ka [1.6K]3 years ago

5 0

Your answer would be h<5ft. This is because this sign '<' means less than. So Brigitte's height is less than 5 ft. Glad I could help!

KonstantinChe [14]3 years ago

3 0

Brigitte is shorter than 5 feet. (Brigitte's height=h)

We write this in inequality form

Brigitte's height is h

So 'h' is shorter than 5 feet

Shorter means less than so we use < symbol. We should not use = symbol because height is shorter than 5 not equal to 5.

Suppose if it is given ' height is more than 5 feet ' then we use greater than symbol (>)

h is less than 5 feet

h < 5

Inequality is h < 5

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tatuchka [14]

Asked and answered elsewhere.
brainly.com/question/10629871

How do you calculate it? You start by expressing the density in the units you have. Then you multiply by appropriate conversion factors to get to the units you want. Treat units as though they were any other variable. A value cancels that appears in both the numerator and denominator of a fraction.

$\dfrac{56.15\,kg}{0.222\,hh}\cdot \dfrac{1000\,g}{1\,kg}\cdot \dfrac{1\,pw}{1.55\,g}\cdot \dfrac{1\,hh}{238.5\,L}\cdot \dfrac{9.091\,L}{1\,pk}\\\\=\dfrac{56.15\cdot 1000\cdot 9.091\,pw}{0.222\cdot 1.55\cdot 238.5\,pk}\\\\ \approx6220\,\frac{pw}{pk}$

5 0

3 years ago

Someone help please:

frozen [14]

Answer:

The sharing cone holds about 9 times more popcorn than the skinny cone.

Step-by-step explanation:

Cone volume:

$V = \frac{\pi r^{2}h}{3}$

r is the radius and h is the inches.

Skinny-size cone:

Radius is r, height h. So

$V_{sk} = \frac{\pi r^{2}h}{3}$

Sharing size:

Radius is now 3r. So

$V_{sh} = \frac{\pi (3r)^{2}h}{3} = \frac{9\pi r^{2}h}{3} = 3\pi r^{2}h$

How many times more popcorn?

$r = \frac{V_{sh}}{V_{sk}} = \frac{3\pi r^{2}h}{\frac{\pi r^{2}h}{3}} = \frac{3*3\pi r^{2}h}{\pi r^{2}h} = 9$

The sharing cone holds about 9 times more popcorn than the skinny cone.

6 0

3 years ago

Help me with this pls

beks73 [17]

The answer is B as I believe

8 0

3 years ago

Read 2 more answers

Compare the temperature change for the two masses of cold water (50 grams and 100 grams) when the same amount of hot water was a

Vesnalui [34]

Answer:

Step-by-step explanation:

All other things being equal (and there are a lot of other things) the 50 gram mass will show a larger temperature

increase than the 100 gram mass.

Why?

The formula is the same from both masses of water (50 grams and 100 grams)

The amount of heat added is the same. (Instead of using hot water, we'll a hot plate on a very low temperature but above what they are now.).

We'll leave it on until we see a rise in temperature delta(t1) = 10 degrees

mc delta(t) = m1 * c * delta(t1)

m = 100

m1 = 50 grams.

c is going to be divided out

we'll solve for the ratio of delta(t) / delta(t1)

100 * delta(t) = 50 (delta(t1)

100 * delta(t) = 50*10

delta(t) = 50*10/100

delta(t) = 5 degrees.

Though this may look rather convoluted, the result is telling us is that delta(t1) for the 50 gram mass is twice as big as as for the 100 gram mass.

The 100 gram mass only rises 5 degrees.

The 50 gram mass rises 10 degrees.

7 0

3 years ago

When a=5, calculate a^2.

Naddik [55]

Answer:

25

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers