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3 years ago

Whats 45+54+22 whats the answer

Mathematics

2 answers:

sveticcg [70]3 years ago

8 0

The answer to MY question is 62

serg [7]3 years ago

6 0

4 x 5 + 5 x 4 + 22
using order of operations (pemdas) we know we need to multiply first

20+20+22
then add

62 is your answer

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Solve the equation. Check your solution. - 6y + 5 = 29y - 2

mr_godi [17]

Answer:

y = 0.2

Step-by-step explanation:

Simplifying

-6y + 5 = 29y + -2

Reorder the terms:

5 + -6y = 29y + -2

Reorder the terms:

5 + -6y = -2 + 29y

Solving

5 + -6y = -2 + 29y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-29y' to each side of the equation.

5 + -6y + -29y = -2 + 29y + -29y

Combine like terms: -6y + -29y = -35y

5 + -35y = -2 + 29y + -29y

Combine like terms: 29y + -29y = 0

5 + -35y = -2 + 0

5 + -35y = -2

Add '-5' to each side of the equation.

5 + -5 + -35y = -2 + -5

Combine like terms: 5 + -5 = 0

0 + -35y = -2 + -5

-35y = -2 + -5

Combine like terms: -2 + -5 = -7

-35y = -7

Divide each side by '-35'.

y = 0.2

Simplifying

y = 0.2

3 0

2 years ago

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The sixth grade is raising money for a camping trip that costs $2,500. So far they have raised 70% of the cost. How much have th

ratelena [41]

Answer:

Step-by-step explanation:

They have raised $1,750 so far. 70% of $2,500 is $1,750

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2 years ago

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e) Given the following: Let X = {1, 2, 3, 4) and a relation R on X as R= {(1,2), (2,3), (3,4)}. Find the reflexive and transitiv

Naddika [18.5K]

Answer:

The answer is $\{(1,1),(2,2),(3,3),(4,4),(1,2)(2,3)(3,4),(1,3),(1,4)\}$

Step-by-step explanation:

Remember that a reflexive relation $R\subset \mathcal{P}(X)$ , where $\mathcal{P}(X)$ is the power set of $X$ , is one which conteins the ordered pairs of the form $(a,a)$ , for $a\in X$ .

So, As the reflexive and transitive closure of $R$ (that we will denote by $\overline{R}$ ) is in particular reflexive, we must add to $R$ the elements $\{(1,1) , (2,2),(3,3),(4,4) \}$

A transitive relation $R$ is one in which if the pair $(a,b)$ and the pair $(b,c)$ are in there, then the pair $(a,c)$ must be there too.

So, to complete the relation $R$ to be reflexive and transitive we must add the pair $(1,3)$ (because $(1,2),(2,3)$ are in $R$ ), the pair $(2,4)$ , and the pair $(1,4)$ because we added the pair $(2,4)$ .