Answer:
71
Step-by-step explanation:
<u>refer</u><u> </u><u>the</u><u> attachment</u>
to solve the question we need to recall one of the most important theorem of circle known as two tangent theorem which states that <u>tangents </u><u>which</u><u> </u><u>meet </u><u>at</u><u> the</u><u> </u><u>same</u><u> </u><u>point</u><u> </u><u>are </u><u>equal</u><u> </u><u> </u>that is being said
since
and it's given that FA and BA are 17 and 29 FB should be
therefore,
once again by two tangent theorem we acquire:
As BC=BH+CH,BC is
- 12+2.5

likewise,AD=AI+DI so,
- 21=17+DI [AD=21(given) and AI=17 (by the theorem)]
thus,
- DI=21-17=

By the theorem we obtain:
Similarly,DC=DG+CH therefore,
- DC=4+2.5=

Now <u>finding</u><u> </u><u>the</u><u> </u><u>Perimeter</u><u> </u><u>of </u><u>ABCD</u>
substitute what we have and got
simplify addition:
hence,
the Perimeter of ABCD is <u>7</u><u>1</u>
Answer: it’s asking where do the points meet at hopes this helps
Step-by-step explanation:
Solution: The formula for mean is:

Where:
is the sum of given observations
is the number of observations


rounded to two decimal places
To find the median, we need to first arrange the data in ascending order but we are already given the data in ascending order.
Therefore, the median is:






Therefore, the median = 1.53
<h3>
Answer: Choice B</h3>
=========================================================
Explanation:
The rule we use is
![\Large a^{m/n} = \sqrt[n]{a^m} = \left(\sqrt[n]{a}\right)^m](https://tex.z-dn.net/?f=%5CLarge%20a%5E%7Bm%2Fn%7D%20%3D%20%5Csqrt%5Bn%5D%7Ba%5Em%7D%20%3D%20%5Cleft%28%5Csqrt%5Bn%5D%7Ba%7D%5Cright%29%5Em)
where 'a' is the base, m stays in the role of the exponent, and n plays the role of the root index (eg: n = 3 is a cube root, n = 4 is a fourth root, and so on).
So for instance,
![\Large 2^{3/4} = \sqrt[4]{2^3} = \left(\sqrt[4]{2}\right)^3](https://tex.z-dn.net/?f=%5CLarge%202%5E%7B3%2F4%7D%20%3D%20%5Csqrt%5B4%5D%7B2%5E3%7D%20%3D%20%5Cleft%28%5Csqrt%5B4%5D%7B2%7D%5Cright%29%5E3)
or in this case,
![\Large t^{5/8} = \sqrt[8]{t^5} = \left(\sqrt[8]{t}\right)^5](https://tex.z-dn.net/?f=%5CLarge%20t%5E%7B5%2F8%7D%20%3D%20%5Csqrt%5B8%5D%7Bt%5E5%7D%20%3D%20%5Cleft%28%5Csqrt%5B8%5D%7Bt%7D%5Cright%29%5E5)
Answer:
just add all sides from the letters it says
Step-by-step explanation:
for an example a has a number b has a number c has a number add all of them together. Hope this helps!