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Murrr4er [49]
3 years ago
7

Find the product. -7(8 + k) 1.-56+7k 2.-7k - 56 3.-7k + 56

Mathematics
1 answer:
Akimi4 [234]3 years ago
4 0
<span>-7(8 + k) 
= -7(8) -7(k)
= -56 - 7k
= -7k - 56

answer
</span><span>2.-7k - 56</span>
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9, 14, 14, 19, 19 is this geometric or arithmetic or neither if neither give the next two sequence
den301095 [7]
Add 5 to 19 and get 24 24
7 0
4 years ago
Find the approximate value of √191 to the nearest tenth. What 2 numbers does it fall between when placed on a number line?
meriva

The approximate value of √191 to the nearest tenth is 13.8 and the two numbers that should fall on the number line is between 13-13.5.

Given that,

  • The square root of √191.

So, the approximate value of √191 is

= \sqrt{191} \\\\= 13.82\\\\

= 13.8

It shows that the two numbers that should fall between at the time when place on the number line is between 13-13.5.

Therefore we can conclude that the approximate value of √191 to the nearest tenth is 13.8 and the two numbers that should fall on the number line are between 13-13.5.

Learn more about the number line here: brainly.com/question/16191404

7 0
3 years ago
Write the equation of the parabola that has the vertex at point (− 1/2 ,2.3) and passes through the point (5,2 3/4 ).
Alex73 [517]

Answer:

The equation of parabola in vertex form is y=0.015(x+0.5)^2+2.3

Step-by-step explanation:

Given coordinate of vertex is (-\frac{1}{2},2.3) and the parabola passes through the point (5,2\frac{3}{4})

So, the equation of parabola in vertex form is

y=a(x-h)^2+k

Where (h,k) is the coordinate of the vertex.

(h,k)=(-\frac{1}{2},2.3)=(-0.5,2.3).\\\\So,\ h=-0.5\ and\ k=2.3

Plugging these value in equation we get,

y=a(x-(-0.5))^2+2.3\\\\y=a(x+0.5)^2+2.3

Now, we will find the value of a

Plug the coordinate (5,2\frac{3}{4})

(x,y)= (5,2\frac{3}{4})\\\\(x,y)=(5,\frac{11}{4})\\\\(x,y)=(5,2.75)

2.75=a(5-(-0.5))^2+2.3\\\\2.75=a(5+(0.5))^2+2.3\\\\2.75=a(5.5)^2+2.3\\\\2.75=a\times30.25+2.3\\\\2.75-2.3=a\times30.25\\\\0.45=a\times30.25\\\\\frac{0.45}{30.25}=a\\ \\a=0.0149

Plug the value of a in the equation y=a(x+0.5)^2+2.3

So, the equation of parabola with vertex (-\frac{1}{2},2.3) and passes through the point (5,2\frac{3}{4}) is

y=0.0149(x+0.5)^2+2.3 ≅y=0.015(x+0.5)^2+2.3

5 0
3 years ago
Please help! I'll give brainlist!
Blababa [14]

Answer:

36°

Step-by-step explanation:

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8 0
3 years ago
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A cell phone company charges a $36 activation fee and $49 every
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