I need help please!!

Which angles are complementary<br> to <1. Select all that apply.

lbvjy [14]

Answer:

∠5

Step-by-step explanation:

Complementary angles are angles that:

sum to 90°
make a right angle

Given this information, angles 2, 3, and 4 are already right angles. That leaves angle 5 and angle 1 to be complementary with each other, as they form a right angle.

Have a lovely rest of your day/night, and good luck with your assignments! ♡

~ ren

4 0

2 years ago

Stephon makes the following statements: statement 1 lim x -3 f(x) exists and is equal to 1 statement 2 lim x 1 f(x) exists and i

Mandarinka [93]

Neither statement 1, nor statement 2 are correct

The given Stephon's statements are;

Statement 1; $\mathbf{\lim \limits _{x \to -3} f(x)} \ \mathbf{Exist} \ and \mathbf{\lim \limits _{x \to -3} f(x) = 1}$

Statement 2; $\mathbf{\lim \limits _{x \to 1} f(x)} \ \mathbf{Exist} \ and \mathbf{\lim \limits _{x \to 1} f(x) = 1}$

The analysis of the graph and reason for the answer

From the graphed line on the left of the y-axis, we have an open circle at x = -3, and an arrow at the other end pointing towards negative infinity, (-∞) which indicates that the domain is -∞ ≤ x < -3, therefore, at x = -3, f(x) does not exist, therefore, we can write the following statement

The limits of the domain and range of the graph includes;

$\mathbf{\lim \limits _{x \to -3} f(x)} = \mathbf{Does \ not \ exist}$

f(x) = Defined for -∞ ≤ x < -3

Similarly, from the graphed line on the right of the y-axis, we have an open circle at x = 1 and an arrow at the other end of the line f(x) = 4 pointing towards positive (+∞) infinity, which indicates the domain and the graph of the function is 1 < x ≤ ∞ , therefore, f(x) does not exist at x = 1, and we can write

$\mathbf{\lim \limits _{x \to 1} f(x)} = \mathbf{Does \ not \ exist}$