I need help please!!

Pls help and dont give wrong answer brain if correct

irinina [24]

Answer:

Step-by-step explanation:

72.5/8.9=8.15

33.2/1.2=27.67

74.3/7.9=9.41

35.5/3.2=11.09

28.1/3.7=7.59

hope this helps

8 0

3 years ago

Read 2 more answers

-2x+3=-2x+5 how do you solve for x

nadezda [96]

Answer:

"no salutions" is your answer

Step-by-step explanation:

4 0

3 years ago

Graph y≤1-3x. ( Which graph ).

Nezavi [6.7K]

Answer:

tidak tU sama sekali

terimakasih atas pengertianya

3 0

3 years ago

Consider the parabola given by the equation: f(x) = 4x² - 6x - 8 Find the following for this parabola: A) The vertex: Preview B)

jeyben [28]

Answer:

The vertex: $(\frac{3}{4},-\frac{41}{4} )$

The vertical intercept is: $y=-8$

The coordinates of the two intercepts of the parabola are $(\frac{3+\sqrt{41} }{4} , 0)$ and $(\frac{3-\sqrt{41} }{4} , 0)$

Step-by-step explanation:

To find the vertex of the parabola $4x^2-6x-8$ you need to:

1. Find the coefficients a, b, and c of the parabola equation

$a=4, b=-6, \:and \:c=-8$

2. You can apply this formula to find x-coordinate of the vertex

$x=-\frac{b}{2a}$ , so

$x=-\frac{-6}{2\cdot 4}\\x=\frac{3}{4}$

3. To find the y-coordinate of the vertex you use the parabola equation and x-coordinate of the vertex ( $f(-\frac{b}{2a})=a(-\frac{b}{2a})^2+b(-\frac{b}{2a})+c$ )

$f(-\frac{b}{2a})=a(-\frac{b}{2a})^2+b(-\frac{b}{2a})+c\\f(\frac{3}{4})=4\cdot (\frac{3}{4})^2-6\cdot (\frac{3}{4})-8\\y=\frac{-41}{4}$

To find the vertical intercept you need to evaluate x = 0 into the parabola equation

$f(x)=4x^2-6x-8\\f(0)=4(0)^2-6\cdot 0-0\\f(0)=-8$

To find the coordinates of the two intercepts of the parabola you need to solve the parabola by completing the square

$\mathrm{Add\:}8\mathrm{\:to\:both\:sides}$

$x^2-6x-8+8=0+8$

$\mathrm{Simplify}$

$4x^2-6x=8$

$\mathrm{Divide\:both\:sides\:by\:}4$

$\frac{4x^2-6x}{4}=\frac{8}{4}\\x^2-\frac{3x}{2}=2$

$\mathrm{Write\:equation\:in\:the\:form:\:\:}x^2+2ax+a^2=\left(x+a\right)^2$

$x^2-\frac{3x}{2}+\left(-\frac{3}{4}\right)^2=2+\left(-\frac{3}{4}\right)^2\\x^2-\frac{3x}{2}+\left(-\frac{3}{4}\right)^2=\frac{41}{16}$

$\left(x-\frac{3}{4}\right)^2=\frac{41}{16}$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

$x_1=\frac{\sqrt{41}+3}{4},\:x_2=\frac{-\sqrt{41}+3}{4}$

4 0

3 years ago

In your biology class, your final grade is based on several things: a lab score, scores on two major tests, and your score on th

WARRIOR [948]

Answer:

$Weighted\ Average = 73$

Step-by-step explanation:

Given

$Lab = 21\%$

$Tests = 25\%$

$Exam = 29\%$

$Lab\ Score = 60$

$First\ Test = 81$

$Second\ Test = 69$

$Exam = 79$

Required

The weighted average

To do this, we simply multiply each score by the corresponding worth.

i.e.

$Weighted\ Average = Lab\ worth * Lab\ score + Tests\ worth * Tests\ score.....$

So, we have:

$Weighted\ Average = 21\% * 60 + 25\% * 81 + 25\% * 69 + 29\% * 79$

Using a calculator, we have:

$Weighted\ Average = 73.01$

$Weighted\ Average = 73$ --- approximated

4 0

3 years ago