Answer:
Volume of the frustum = ⅓πh(4R² - r²)
Step-by-step explanation:
We are to determine the volume of the frustum.
Find attached the diagram obtained from the given information.
Let height of small cone = h
height of the large cone = H
The height of a small cone is a quarter of the height of the large cone:
h = ¼×H
H = 4h
Volume of the frustum = volume of the large cone - volume of small cone
volume of the large cone = ⅓πR²H
= ⅓πR²(4h) = 4/3 ×π×R²h
volume of small cone = ⅓πr²h
Volume of the frustum = 4/3 ×π×R²h - ⅓πr²h
Volume of the frustum = ⅓(4π×R²h - πr²h)
Volume of the frustum = ⅓πh(4R² - r²)
I didn’t learn this yet but maybe
Answer:20.00
Step-by-step explanation: next time include the table but i managed to find it anyway
Answer:
x-ints: (2,0) & (4,0)
y-int: (0,-8)
vertex: (3,1) *highest point of the graph
line of symmetry: x = 3 *x-value in the middle of x-ints
a value is -# *if parabola points done it's negative, if it points up it's positive
Answer:
a = x² + 3x - 40
Step-by-step explanation:
a = l * w
a = (x - 5)(x + 8)
a = x(x + 8) - 5(x + 8)
a = (x² + 8x) + (- 5x - 40)
a = x² + 3x - 40