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Rus_ich [418]
3 years ago
6

Which equation is the inverse of 5 y + 4 = (x + 3) squared + one-half?

Mathematics
2 answers:
telo118 [61]3 years ago
8 0

Answer:

The correct option is the last option d.) y = negative 3 plus-or-minus StartRoot 5 x + seven-halves EndRoot

Step-by-step explanation:

the given equation is 5y + 4 =(x+3)^{2}  + \frac{1}{2}

Therefore we can write 5y\hspace{0.1cm} = (x+3)^{2} + \frac{1}{2} - 4  \hspace{0.3cm}   \Rightarrow  \hspace{0.2cm}  5y = (x+3)^{2} - \frac{7}{2}   \hspace{0.3cm} \Rightarrow \hspace{0.3cm}  y = \frac{(x+3)^{2}}{5} - \frac{7}{10}

To find the inverse of the above function let us replace x with y and y with x.

Therefore we get

x = \frac{(y+3)^{2}}{5} - \frac{7}{10}

Now we write the above equation with only y on the Left hand side and we will obtain the inverse of the given function

y = \pm \sqrt{5 (x + \frac{7}{10} )} \hspace{0.1cm} - \hspace{0.1cm} 3 \hspace{0.1cm} \Rightarrow\hspace{0.1cm}  y =  \pm \sqrt{5x + \frac{7}{2} }  - \hspace{0.1cm} 3 \hspace{0.1cm}

Therefore the correct option is the last option d.) y = negative 3 plus-or-minus StartRoot 5 x + seven-halves EndRoot , y =  \pm \sqrt{5x + \frac{7}{2} }  - \hspace{0.1cm} 3 \hspace{0.1cm}

ohaa [14]3 years ago
4 0

Answer:

y = negative 3 plus-or-minus StartRoot 5 x + seven-halves EndRoot

Step-by-step explanation:

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