All categories

3 years ago

Can someone help me on this plz thankyou!!

Mathematics

1 answer:

kipiarov [429]3 years ago

4 0

G(x) is a translation of f(x) 5 units up
Giving us g(x)=f(x)+5
So k=5

You might be interested in

Whats thr answer to this? 3( -2d + 1) (pre alg)

sineoko [7]

Answer:

here

Step-by-step explanation:

if all you're doing is distributing it, the answer is -6d + 3

8 0

2 years ago

Porfaaaaa ayudaaa necesito la respuesta rapido plsss

MariettaO [177]

Answer:

Step-by-step explanation:

5 0

4 years ago

If the legs of a right triangle are both 8 cm, find the area of the triangle.

tankabanditka [31]

Answer: 32 Cm squared

Step-by-step explanation:

The area of a triangle is (1/2) base times height.

(1/2) x (8) x (8) = 32

5 0

4 years ago

Read 2 more answers

Which is the intersection of XY¯¯¯¯¯¯ and XZ¯¯¯¯¯?

KIM [24]

Answer:

A) X

Step-by-step explanation:

It is assumed we are talking about two rays XY and XZ.

They intersect at common point X.

Correct choice is A

7 0

3 years ago

Read 2 more answers

The equation a = StartFraction one-half EndFraction left-parenthesis b 1 plus b 1 right-parenthesis.(b1 + b2)h can be used to de

aleksley [76]

Answer:

The equivalent expressions are:

$b1=\frac{2a}{h}-b2$

$h=\frac{2a}{b1+b2}$

Step-by-step explanation:

Given equation for finding area of a trapezoid:

$a=\frac{1}{2}(b1+b2)h\\$

where $a$ represents area, $h$ represents height and $b1\ and\ b2$ represents the base lengths of the trapezoid.

Evaluating $h$ by rearranging the equation to find an equivalent equation.

Multiplying both sides by 2.

$2\times a=2\times\frac{1}{2}(b1+b2)h$

$2a=(b1+b2)h$

Dividing both sides by $b1+b2$

$\frac{2a}{b1+b2}=\frac{(b1+b2)h}{b1+b2}$

$\frac{2a}{b1+b2}=h$

$\therefore h=\frac{2a}{b1+b2}$

Evaluating $b1$ by rearranging the equation to find an equivalent equation.

Multiplying both sides by 2.

$2\times a=2\times\frac{1}{2}(b1+b2)h$

$2a=(b1+b2)h$

Dividing both sides by $h$

$\frac{2a}{h}=\frac{(b1+b2)h}{h}$

$\frac{2a}{h}=b1+b2$

Subtracting both sides by $b2$

$\frac{2a}{h}-b2=b1+b2-b2$

$\frac{2a}{h}-b2=b1$

$\therefore b1=\frac{2a}{h}-b2$

8 0

3 years ago

Read 2 more answers