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3 years ago

Between x = 0 and x = 1, which function has the same average rate of change as y = 3x ?

Mathematics

2 answers:

Nataly [62]3 years ago

7 0

Answer:

D) y = 1/3-x

Step-by-step explanation:

The average rate of changes for each of the functions between 0 and 1 is 8, 3, 1, and 2. The average rate of change of y = 3x is 2. Therefore the same average rate of change is 2, which is the function y = 1/3-x

iren2701 [21]3 years ago

3 0

Answer:

Answer is d

Step-by-step explanation:

took it

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Find the Pearson correlation coefficient R for the given point round any intermediate calculation to no less than six decimal pl

ElenaW [278]

SOLUTION

Given the question in the image, the following are the solution steps to answer the question.

STEP 1: Get the given data values

STEP 2: Write the formula for calculating the coefficient

STEP 3

: Calculate the correlation coefficient

Using the calculator,

Hence, the value of r is 0.791

7 0

1 year ago

Can someone help me

erik [133]

Answer:

6 < x < 23.206

Step-by-step explanation:

To properly answer this question, we need to make the assumption that angle DAC is non-negative and that angle BCA is acute.

The maximum value of the angle DAC can be shown to occur when points B, C, and D are on a circle centered at A*. When that is the case, the sine of half of angle DAC is equal to 16/22 times the sine of half of angle BAC. That is, ...

(2x -12)/2 = arcsin(16/22×sin(24°))

x ≈ 23.206°

Of course, the minimum value of angle DAC is 0°, so the minimum value of x is ...

2x -12 = 0

x -6 = 0 . . . . . divide by 2

x = 6 . . . . . . . add 6

Then the range of values of x will be ...

6 < x < 23.206

_____

* One way to do this is to make use of the law of cosines:

22² = AB² + AC² -2·AB·AC·cos(48°)

16² = AD² + AC² -2·AD·AC·cos(2x-12)

The trick is to maximize x while satisfying the constraints that all of the lengths are positive. This will happen when AB=AC=AD, in which case the equations be come ...

22² = 2·AB²·(1-cos(48°))

16² = 2·AB²·(1 -cos(2x-12))

The value of AB drops out of the ratio of these equations, and the result for x is as above.

4 0

3 years ago

Read 2 more answers

What are two expressions that are equivalent to 6(5j + 2 + j)?<br><br><br><br>

ziro4ka [17]

Answer:

1. 30j+12+6j

2. 36j+12

3. 6(6j+2)

Step-by-step explanation:

1. You just multiply so... 6x5j ... 6x2 ... 6xj

2. you multiply and then simplify so first you have 30j+12+6j, so you add like terms so... 30j+6j= 36j and then +12

3. you do what's in the parentheses first so 5j+j=6j so .... 6(6j+2)

5 0

4 years ago

How does the graph of y = sec(x + 3) – 7 compare with the graph of y = sec(x)?

Alla [95]

Answer:

The function y = sec(x) shifted 3 units left and 7 units down .

Step-by-step explanation:

Given the function: y = sec(x)

If k is any positive real number, then the graph of f(x) - k is the graph of y = f(x) shifted downward k units.

If p is a positive real number, then the graph of f(x+p) is the graph of y=f(x) shifted to the left p units.

The function $y = \sec(x+3)-7$ comes from the base function y= sec(x).

Since 3 is added added on the inside, this is a horizontal shift Left 3 unit, and since 7 is subtracted on the outside, this is a vertical shift down 7 units.

Therefore, the transformation on the given function is shifted 3 units left and 7 units down

3 0

3 years ago

Read 2 more answers

Elena has $225 in her bank account. She takes out $20 each week for w weeks. After w weeks she has d dollars left in her bank ac

Diano4ka-milaya [45]

Answer:

225 - 20w = d

Step-by-step explanation:

7 0

4 years ago

Read 2 more answers