Answer:
The speed of the first train is 45 mph and the speed of the second train is 75 mph
Step-by-step explanation:
Let x represent the speed of the first train in mph. Since the second train, is 30 mph faster then the first, therefore the speed of the second train is (x + 30).
The first train leaves at 1:00 pm, therefore at 6:00 pm, the time taken is 5 hours. Therefore the distance covered by the first train at 6:00 pm = x mph * 5 hours = 5x miles
The second train leaves at 3:00 pm, therefore at 6:00 pm, the time taken is 3 hours. Therefore the distance covered by the second train at 6:00 pm = (x + 30) mph * 3 hours = (3x + 90) miles
Since the second train overtakes the first at 6:00 pm, hence:
3x + 90 = 5x
2x = 90
x = 45
Therefore the speed of the first train is 45 mph and the speed of the second train is 75 mph (45 mph + 30 mph).
Answer:
y = 65
Step-by-step explanation:
45 + 57 = x + y
x = 37
45 + 57 = 37 + y
45 + 57 = 102
102 = 37 + y
102 = 37 + y
-37 -37
102 - 37 = 65
37 + y - 37 = y
65 = y
y = 65
Answer:
First option: 10 - (1) = 9
Second option: 10 - 5 + 4 = 5 + 4 = 9
Step-by-step explanation:
(10 -5) -4 = 5 - 4 = 1
Equivalent equation: 10 - 5 - 4 = 1
10 - (5-4) = there would be 2 ways to do this, you can either solve the equation in the bracket first or break it out. Because the sign before the bracket is minus so when you break it out, the minus sign in the bracket would become -- or equal to +
First option: 10 - (1) = 9
Second option: 10 - 5 + 4 = 5 + 4 = 9
Hope this help you:3
Answer:
<h2>
The width, x, of this parallelogram is 16 cm.</h2>
Step-by-step explanation:
In #14, the area of the parallelogram is 528 cm².
This area is also the value of the formula A = L·W:
A = 528 cm² = (33 cm)·W
To determine the width, W, of this parallelogram, we perform the following division:
W = (528 cm²) / (33 cm) = 16 cm
The width, x, of this parallelogram is 16 cm.
A=πr2
A=3.14 x 6 x 6
answer=113.04