Answer:
Explanation:
using the formula p² + 2pq + 2pr + q²+ 2qr + r² = 1 where p is IA allele is 0.35 and q is IB allele is 0.15.
Thus, the expected frequency of people with type AB blood in this population will be (2pq) = 2 x 0.35 x 0.15 = 0.105
b. The expected frequency of people with type A blood will be p² + 2pr = where r is found using the formular p + q + r = 1 = 1 - (p+q) = 1 - (0.35+0.15) = 0.5
Thus, we have the expected frequency of people with type A blood to be (0.35² + 2x0.35x0.5) = 0.4725.
c. <u> p² + 2pr</u> + <u>2pq </u>+ <u>q² + 2qr</u> +<u> r²</u>
AA AO AB BB BO OO
1850 180 635 2335
frequency of IA- p = (1850 + 180/2) / 5000 = 0.388
frequency of IB- q = (635 + 180/2) / 5000 = 0.145
frequency of i- r = 2335/ 5000 = 0.467.
since r² = 2335, r = √2335 = 48.32
using the formula p + q + r = 1
The best answer for the above question would be letter b- shape.
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From single-celled ancestors, they evolved into a riot of complexity and diversity. An estimated seven million species of animals live on earth today, ranging from tubeworms at the bottom of the ocean to elephants lumbering across the African savanna.
Answer:
This is hard to answer as I need pictoral evidence for it.
Explanation:
Maybe add a little picture to go with question