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Murrr4er [49]
3 years ago
6

how many leaves on a tree diagram are needed to represent all possible combinations tossing a coin 3 times

Mathematics
1 answer:
Lelechka [254]3 years ago
6 0
I believe you would do 2 times 3, which gives you 6. 3 is for the number of coin tosses, and 2 is the number of sides of a coin.
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Ivahew [28]

11.25/375 = 0.03 which is 3%

4 0
3 years ago
Help quick ❗️❗️ Which sequence of transformations will change did your PQRS to figure P’Q’R’S’?
babymother [125]

Answer:

Counterclockwise rotation about the origin by 90° followed by reflection over the Y-axis ⇒ answer (D)

Step-by-step explanation:

* Lets revise the reflection and the rotation of a point

- If point (x , y) reflected across the x-axis

∴ Its image is (x , -y)

- If point (x , y) reflected across the y-axis

∴ Its image is (-x , y)

- If point (x , y) rotated about the origin by angle 90° counter clockwise

∴ Its image is (-y , x)

- If point (x , y) rotated about the origin by angle 90° clockwise

∴ Its image is (y , -x)

- If point (x , y) rotated about the origin by angle 180°

∴ Its image is (-x , -y)

* There is no difference between rotating 180° clockwise or  

anti-clockwise around the origin

- In our problem

# The vertices of the original figure are:

  P(1 , -3) , Q (3 , -2) , R (3 ,-3) , S (2 , -4)

# The vertices of the image are:

  P' (-3 , 1) , Q' (-2 , 3) , R' (-3 , 3) , S' (-4 , 2)

∵ x and y are switched

∴ The figure is rotated about origin by 90°

∵ The signs of the x-coordinates and the y-coordinates

   didn't change

∴ The rotation is followed by reflection, to know about which

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∵ Q (3 , -2) ⇒ after rotation 90° counter clockwise is (2 , 3)

∵ R (3 , -3) ⇒ after rotation 90° counter clockwise is (3 , 3)

∵ S (2 , -4) ⇒ after rotation 90° counter clockwise is (4 , 2)

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- The sign of x-coordinates of all of them changed

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7 0
3 years ago
There is a bag with only red marbles and blue marbles.
Lostsunrise [7]

Answer:

60 marbles in total

Step-by-step explanation:

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42/0.7

= 60

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8 0
3 years ago
A poster is to have a total area of 125 cm2. There is a margin round the edges of 6 cm at the top and 4 cm at the sides and bott
jeka57 [31]

Answer:

The correct answer is 15 cm.

Step-by-step explanation:

Let the width of the required poster be a cm.

We need to have a 6 cm margin at the top and a 4 cm margin at the bottom. Thus total margin combining top and bottom is 10 cm.

Similarly total margin combining both the sides is (4+4=) 8 cm.

So the required printing area of the poster is given by {( a-10 ) × ( a - 8) } cm^{2}

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By law of trichotomy the possible values of a are 15 and 3.

But a=3 is absurd as a > 4.

Thus the required answer is 15 cm.

7 0
3 years ago
Read 2 more answers
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Veseljchak [2.6K]
The answer is YES because of the triple negative and double negative
6 0
3 years ago
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