A prime number is a natural number greater than 1 that cannot be formed by multiplying two smaller natural numbers
Step-by-step explanation:
Answer:
Explanation:
Since, there are two possible outcomes for every toss (head or tail), the sample space for<em> a coin tossed 8 times</em> is 2×2×2×2×2×2×2×2 = 2⁸ = 256.
<em>Landing on heads all 8 times</em> is just one of the possible outcomes: HHHHHHHH ⇒ 1.
Hence, the <em>probability </em>is calculated from its own definition:
Probability = number of favorable outcomes / number of possible outcomes
Answer: Area is 20
Step-by-step explanation:
Perimeter of a rectangle is 24
Let the length be x
Let the breadth be Y
Length is 5times the breadth
I.e
X=5y
Formula for perimeter of a rectangle is
2(length + breadth)
= 2(x+y)
Substitute for x=5y
2(5y+y)=24
2(6y)=24
6y=24/2
6y=12
Y=12/6
Y=2
Breadth = 2
Since length =5y
Length=5(2)
Length = 10
Area of a rectangle = length × breadth
Area= 10×2
Area = 20
Area of the rectangle is 20
Answer:
maximum height is 4.058 metres
Time in air = 0.033 second
Step-by-step explanation:
Given that the equation height h
h = -212t^2 + 7t + 4
What is the toy's maximum height?
Let us assume that the equation is a perfect parabola
Time t at Maximum height will be
t = -b/2a
Where b = 7 and a = - 212
t = -7/ - 212 ×2
t = 7/ 424 = 0.0165s
Substitute t in the main equation
h = - 212(7/424)^2 + 7(7/424) + 4
h = - 0.05778 + 0.115567 + 4
h = 4.058 metres
Therefore the maximum height is 4.058 metres
How long is the toy in the air?
The object will go up and return to the ground.
At ground level, h = 0
-212t^2 + 7t + 4 = 0
212t^2 - 7t - 4 = 0
You can factorize the above equation and pick the positive time t since time can't be negative
Or
Since we have assumed that it's a perfect parabola,
Total time in air = (-b/2a) × 2
Time in air = 0.0165 × 2 = 0.033 s
Answer:
The gcf of 42 and 48 can be obtained like this:
The factors of 42 are 42, 21, 14, 7, 6, 3, 2, 1.
The factors of 48 are 48, 24, 16, 12, 8, 6, 4, 3, 2, 1.
The common factors of 42 and 48 are 6, 3, 2, 1, intersecting the two sets above.
In the intersection factors of 42 ∩ factors of 48 the greatest element is 6.
Therefore, the greatest common factor of 42 and 48 is 6.
Taking the above into account you also know how to find all the common factors of 42 and 48, not just the greatest.
Hope I helped
