Answer:
The sum of all the sides to this quadrilateral will equal a total of 20 inches, so you set up the equation:
2 + 2x + 7 + x + 2 = 20
Solve for x by combining like terms;
(2 + 7 + 2) + (2x + x) = 20
Which simplifies to;
11 + 3x = 20
Get rid of constants;
-11 -11
3x = 9
Isolate x by getting rid of it's coefficient;
/3 /3
<u>x = 3</u>
Now, to find the length of PQ, we plug in the value of x(3) into the equation that contains the line PQ.
x + 2
<u>3</u> + 2
= <u>5 inches.</u>
Now, to find the length of RS, we plug in the value of x(3) into the equation that contains the line RS.
2x
2(3)
= <u>6 inches.</u>
Answer:
![\huge{\purple {r= 2\times\sqrt[3]3}}](https://tex.z-dn.net/?f=%5Chuge%7B%5Cpurple%20%7Br%3D%202%5Ctimes%5Csqrt%5B3%5D3%7D%7D)
![\huge 2\times \sqrt [3]3 = 2.88](https://tex.z-dn.net/?f=%5Chuge%202%5Ctimes%20%5Csqrt%20%5B3%5D3%20%3D%202.88)
Step-by-step explanation:
- For solid iron sphere:
- radius (r) = 2 cm (Given)
- Formula for
is given as:
- For cone:
- r : h = 3 : 4 (Given)
- Let r = 3x & h = 4x
- Formula for
is given as:
- It is given that: iron sphere is melted and recasted in a solid right circular cone of same volume

![\implies \huge{\purple {r= 2\times\sqrt[3]3}}](https://tex.z-dn.net/?f=%5Cimplies%20%5Chuge%7B%5Cpurple%20%7Br%3D%202%5Ctimes%5Csqrt%5B3%5D3%7D%7D)
- Assuming log on both sides, we find:
- Taking antilog on both sides, we find:
Answer:
(6x6x6x6) x (6x6x6)
Step-by-step explanation:
6 to the power of four is just 6 multiplied to itself 4 times.
6 to the power of three is just 6 multiplied to itself 3 times.
So, you would be multiplying 6, 7 times.
You could check it with a calculator. - 6^4 x 6^3 = 279936.
6^7 = 279936.