In order to solve this we must first,
Subtract both sides of the equation by 10,
y-10=1/2x
Now we have to multiply both sides by 2 so that only x is left.
2y-20=x
Therefore, x=2y-20
The gaps in the area needs to be closed so the data you use is lenient
9514 1404 393
Answer:
- 85°
- 60°
Step-by-step explanation:
1. Angle JKL is half the measure of the intercepted arc JK.
(1/2)JK = 1/2(360° -190°) = (1/2)(170°) = 85°
angle JKL is 85°
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2. The angle between tangents is the supplement of the intercepted arc.
angle JKL = 180° -(360° -240°)
angle JKL = 60°
