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Igoryamba
3 years ago
9

A party store sells large plates in packs of 12 and small plates of 8 . in order to have an equal number of both , what is the l

east amount of large plates that would have to be purchased
Mathematics
1 answer:
ycow [4]3 years ago
3 0
The leas amount of large plates that would have to be purchased is 24

So the person would buy 2 packs of large plates and 3 packs of small plates.


How to: the way to find this out, is to find the first multiplication of 8 that is a number equally divided by 12. So you go:
8x1 = 8 (less than 12, so not enough)
8x2 = 16 (more than 12, but still not enough to divide equally)
8x3 = 24 (bingo!)

Hope it helps.
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Jordan flipped a coin 492 times. Which of the following would be a good estimate of the number of times the coin landed on heads
Irina-Kira [14]
I'd say B. but that's only because I divided the number of times he flipped the coin by the number of sides it has, 2, and came up with 246. The closest number on here to that is 231 or B. I hope I helped.
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3 years ago
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Use a Venn diagram to answer the question. A survey of 180 families showed that 67 had a​ dog; 52 had a​ cat; 22 had a dog and a
Mice21 [21]

Answer:

There are 13 families had a parakeet only

Step-by-step explanation:

* Lets explain the problem

- There are 180 families

- 67 families had a dog

- 52 families had a cat

- 22 families had a dog and a cat

- 70 had neither a cat nor a​ dog, and in addition did not have a​

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- 4 had a​ cat, a​ dog, and a parakeet (4 is a part of 22 and 22 is a part

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* We will explain the Venn-diagram

- A rectangle represent the total of the families

- Three intersected circles:

 C represented the cat

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- The common part of the three circle had 4 families

- The common part between the circle of the cat and the circle of the

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- The common part between the circle of the dog and the circle of the

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- The common part between the circle of the cat and the circle of the

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- The non-intersected part of the circle of the dog had 67 - 22 - a =

  45 - a families

  had dogs only

- The non-intersected part of the circle of the cat had 52 - 22 - b =  

  30 - b families

  had cats only

- The non-intersected part of the circle of the parakeet had c families

  had parakeets only

- The part out side the circles and inside the triangle has 70 families

- Look to the attached graph for more under stand

∵ The total of the families is 180

∴ The sum of all steps above is 180

∴ 45 - a + 18 + 4 + 30 - b + b + c + a + 70 = 180 ⇒ simplify

- (-a) will cancel (a) and (-b) will cancel (b)

∴ (45 + 18 + 4 + 30 + 70) + (-a + a) + (-b + b) + c = 180

∴ 167 + c = 180 ⇒ subtract 167 from both sides

∴ c = 180 - 167 = 13 families

* There are 13 families had a parakeet only

5 0
3 years ago
Will give brainliest for correct answer ALGEBRA 2
LenKa [72]

Answer:

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Step-by-step explanation:

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Hope this helps :)

7 0
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adoni [48]

Step-by-step explanation:

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Simplify the ratio 0.08:0.12
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