Answer:
9/35
Step-by-step explanation:
There are a total of 15 bulbs to choose from randomly. First a new bulb is chosen. Chance is 9/15 because 9 out of 15 are new.
Then there are only 14 bulbs left. Then a used bulb is chosen. Chance is 6/14 since 6 out of remaining 14 are used.
Total chance for this to happen is 9/15 * 6/14 = 54/210 = 9/35.
Answer:
1) 257
2) 24^1=24
3) 47/8(Decimal: 5.875) How to: 5/1+7/8 = 40/80+7/8 = 40 + 7 / 8 <em>=</em><em> </em><em>4</em><em>7</em><em>/</em><em>8</em>
4)=920
5) =32.484
6) =33.444
7) = 4 : 1 How to: The GCF of 12 and 3 is 3 Divide both terms by the GCF, 3:
12 ÷ 3 = 4
3 ÷ 3 = 1 The ratio 12 : 3 can be reduced to lowest terms by dividing both terms by the GCF = 3 :
12 : 3 = 4 : 1
8) = 9 cups. How to: 2*3=6. so you multiply the other side (3) by 3 so 3*3=9 cups.
9) The second pack weighs more. How to: Since 45 ounces is 2.812 pounds (Formula
divide the mass value by 16) and 2.812 is less than 3 so second pack weighs more.
10) =26.6
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Answer:
f(w) = 120 + 5(30-h)
Step-by-step explanation:
It is given that, Andrew gets paid $4 for first 30 hours of the week
So,
For first 30 hours, his wage will be:
4(30) = $120
Now, let w denote wages and h denote total number or hours he works in the week
So he will be paid $5 for h-30 hours
So the function will be
f(w) = 120 + 5(30-h)
Where $120 is the fixed income for first 30 hours and the second term is the wage of hours more than 30 at the rate of $5 per hour..
Multiplying both sides by 
gives
so that substituting 
and hence 
gives the linear ODE,
Now multiply both sides by 
to get
so that the left side condenses into the derivative of a product.
![\dfrac{\mathrm d}{\mathrm dx}[x^3v]=3x^2](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dx%7D%5Bx%5E3v%5D%3D3x%5E2)
Integrate both sides, then solve for 
, then for 
:
![\boxed{y=\sqrt[3]{1+\dfrac C{x^3}}}](https://tex.z-dn.net/?f=%5Cboxed%7By%3D%5Csqrt%5B3%5D%7B1%2B%5Cdfrac%20C%7Bx%5E3%7D%7D%7D)
