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podryga [215]
3 years ago
5

Simplify completely 3x4+5x2+2x/x​

Mathematics
1 answer:
Andre45 [30]3 years ago
8 0

Step-by-step explanation:

\dfrac{3x^4+5x^2+2x}{x}=\dfrac{x\!\!\!\!\!\diagup^1(3x^3+5x+2)}{x\!\!\!\!\!\diagup_1}=3x^3+5x+2

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What is the factor of <br><img src="https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B2%7D%20%20-%206x%20-%2027" id="TexFormula1" title="
Ksju [112]

Answer:

(x - 9)(x + 3)

Step-by-step explanation:

Given

x² - 6x - 27

Consider the factors of the constant term (- 27) which sum to give the coefficient of the x- term (- 6)

The factors are - 9 and + 3, since

- 9 × 3 = - 27 and - 9 + 3 = - 6, thus

x² - 6x - 27 = (x - 9)(x + 3)

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Find the length of the missing side (nearest tenth).<br> 31 yd<br> 12 yd
marishachu [46]

Answer:

28.6

Step-by-step explanation:

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3 years ago
X/2=1/3 what's the value of x?
FrozenT [24]
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The following are the times, in seconds, that 15 people spent taking an online survey.
elena-s [515]

The only true statement in the distribution is 261.

Given the following values :

125, 91, 261, 25, 155, 105, 195, 132, 110, 143, 121, 99, 167, 165, 160

Arranging the values in ascending order :

25, 91, 99, 105, 110, 121, 125, 132, 143, 155, 160, 165, 167, 195, 261

An outlier can be calculated thus :

Lower boundary = Q1 - (1.5 × IQR)

Upper boundary = Q3 + (1.5 × IQR)

Using a statistical calculator :

Lower quartile, Q1 = 105

Upper quartile, Q3 = 165

IQR = Q3 - Q1 = 165 - 105 = 60

Lower boundary = 105 - (1.5 × 60) = 15

Upper boundary = 165 + (1.5 × 60) = 255

Therefore, values lower than 15 or greater than 255 are outliers.

Hence, the outlier in the distribution is 261.

Learn more : brainly.com/question/24582786

4 0
3 years ago
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