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Yakvenalex [24]
3 years ago
13

Paula bought a jacket on sale for $6 less than half its original price. She paid $36 for the jacket. What was the original price

?
Mathematics
1 answer:
Fudgin [204]3 years ago
4 0

Answer:

The correct answer is $30

Step-by-step explanation:

36-6=30

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This probability distribution shows the typical distribution of pitches thrown to a batter in a given at bat in a baseball game.
Vikki [24]

Answer:

0.35

Step-by-step explanation:

This probability distribution is shown below:

Pitch                   1            2        3          4         5

Frequency         15         20      40        15        10

Probability         0.15     0.2      0.4      0.15      0.1

The probability that the pitcher will throw fewer than 3 pitches to a batter = P(X < 3)

X  is the number of pitches thrown. Therefore:

P(X < 3) = P(X = 1) or P(X = 2)

The additive rule pf probability states that if two events X and Y are dependent events, the probability of X or Y occurring is the sum of their individual probability.

P(X < 3) = P(X = 1) or P(X = 2) = P(X = 1) + P(X = 2) = 0.15 + 0.2 = 0.35

The probability that the pitcher will throw fewer than 3 pitches to a batter = 0.35

8 0
3 years ago
Mr dambek had $90 to spend at the bulls game he spent 31/45 on his ticket the. He spent 3/7 of his remaining money at the conces
slavikrds [6]

Answer:

He does not have enough money to buy the hat.

Step-by-step explanation:

First find out how much he spent on the ticket:

90 \times {31 \over 45}=2 \times 31=62

He spent $62 on the ticket, so he has $90 - $62 = $28 remaining. Now find out how much of that he spent at the concession stand:

28 \times {3 \over 7}=4 \times 3=12

He spent $12 at the concession stand, so he has $28 - $12 = $16 remaining. He does not have enough to buy the $18 hat.

6 0
3 years ago
Solve for y 31=2y-5
DIA [1.3K]

31=2y-5

Add 5 on both -5+5 which cancels out and 31+5 which is 36 and then divide 36 by 2 which equals to 18.

So y=18 hope this helped (':


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False is the correct answer
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Write a proportion that could be used to solve for each variable. Then solve.
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There are 6 balls to every box (a ratio of 6 to 1). Therefore, when there are 78 balls, there are 13 boxes.
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