We are given the function <span>f(x) = 3^x+1 - 2 and is asked for the asymptote and y-intercept. In this case, we transform the function to
y +2 = 1/3^(x+1)-1
y = 1-2</span>/3^(x+1)-1/(3^(x+1)-1)
let 3^(x+1)-1 = 0
<span>1/3^(x+1) = 0
x = infinity
when x = infinity
y = 0 - 2
y = -2
The y-intercept is the value where x = 0. substituting,
y = 3^(0+1) - 2 = 1 </span>
Slope-intercept form is y=mx+b
4y=6x+24
y=6/4x+6
y=3/2x+6
Answer:
Step-by-step explanation:
It would be more obvious if it says z is a standard Normal variable and that the question is related to statistics.
From "Computing Probabilities Using the Cumulative Table" , the probability of z is less than 1.16, P(z<1.16) = 0.8770.
Answer:
He ran 3.25 on Tuesday
Step-by-step explanation:
The answer is 3.25 because 5.55 minus 2.3 is 3.25.
There were 39 more adult tickets sold than children’s tickets