Answer:
First equation is the right answer.
X÷3=0.6
1.8÷3=0.6
0.6=0.6
Hence proved
A line segment from a vertex to the midpoint of the opposite side is a "median". A median divides the area of the triangle in half, as it divides the base in half without changing the altitude.
AAMC is half AABC. AADC is half AAMC, so is 1/4 of AABC. (By the formula for area of a triangle.)
ABMC is half AABC. ABMD is half ABMC, so is 1/4 of AABC. (By the formula for area of a triangle.)
Then, AADC = 1/4 AABC = ABMC, so AADC = ABMC by the transitive property of equality.
Answer:
The table is show clearly in the figure attached.
P(boy if favourite activity is swimming) = 8/17 = 0.47
P(girl if favourite activity is sport) = 7/27 = 0.26
P(girl if favourite activity is reading) = 4/6 = 0.67
P(boy if favourite activity is sport) = 20/27 = 0.74
P(favourite activity is swimming if a girl) = 9/20 = 0.45
P(favourite activity is reading if a boy) = 2/30 = 0.07
P(favourite activity is swimming if a boy) = 8/30 = 0.27
P(favourite activity is reading if a girl) = 4/20 = 0.2
Answer:
The slope or incline is -5
Step-by-step explanation:
rewrite to get the form
y = ...
x - 5y = -10
- 5y = -10 -x
divide left and right if the = sign by -5 gives:
(-5/-5)y = (-1/-5)x + (-10/-5)
y = 1/5x +2
So the incline is 1/5
a perpendicular line has an incline of -1 *5/1 = -5
The slope or incline is -5
