Using the normal distribution, it is found that there is a 0.8413 probability that a randomly chosen box of healthy oats weighs more than 8.8 oz.
<h3>Normal Probability Distribution </h3>In a <em>normal distribution</em> with mean and standard deviation
, the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
In this problem:
- The mean is of 8.9 oz, hence
.
- The standard deviation is of 0.1 oz, hence
.
The probability that a randomly chosen box of healthy oats weighs more than 8.8 oz is <u>1 subtracted by the p-value of Z when X = 8.8,</u> hence:
has a p-value of 0.1587.
1 - 0.1587 = 0.8413.
0.8413 probability that a randomly chosen box of healthy oats weighs more than 8.8 oz.
To learn more about the normal distribution, you can take a look at brainly.com/question/24663213
