<h3>Answer: </h3>
about 1.768 seconds
<h3>Explanation:</h3>
Since the phone is <em>dropped</em>, the first equation applies. The final height is assumed to be zero, so we have ...
... h(t) = 0 = -16t² +50
... 16t² = 50 . . . . . . . . add 16t²
... t² = 50/16 . . . . . . . . divide by 16
... t = √3.125 . . . . . . . take the square root
... t ≈ 1.768 . . . . . . . . round to milliseconds
The possible coordinates for N is 0
The width of the cooling tower at the base of the structure will be A. 36 meters.
<h3>How to calculate the width?</h3>
From the information given, the towers walls are modeled by x²/324 - (y² - 90)²/1600.
Therefore, the width of the cooling tower at the base of the structure will be:
= 2 × ✓324
= 2 × 18
= 36
In conclusion, the width is 36 meters.
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A^2 + b^2 = c^2
3^2 + 8^2 = c^2
9 + 64 = c^2
73 =c^2
take the square root of each side
c= 8.544
