Answer:
Jānis Čakste
Step-by-step explanation:
Let X be the random variable denoting the number of successful throws.
Here X~ Binomial Distribution with n = 5 and p = 0.80.
the probability of her missing 3 (or more) free throws out of 5
= P ( X ≤ 2)
= P (X= 0) + P(X= 1) + P(X= 2)
=0.00032 + 0.0064 + 0.0512
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= 0.05792
I hope my answer has come to your help. God bless and have a nice day ahead!
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The answer is 1.7325
1x5=5
1x2=2
1x8=8
Add a zero
2x5=10
2x2=4
2x8=40
Add a Zero
All the answers to the next number will all be zero.
Add that all together.
(a) The probability of drawing a blue marble at random from a given box is the number of blue marbles divided by the total number of marbles. We assume that the probability of selecting one of two boxes at random is 1/2 for each box.
... P(blue) = P(blue | box1)·P(box1) + P(blue | box2)·P(box2) = (3/8)·(1/2) + (4/6)·(1/2)
... P(blue) = 25/48 . . . . probability the ball is blue
(b) P(box1 | blue) = P(blue & box1)/P(blue) = (P(blue | box1)·P(box1)/P(blue)
... = ((3/8)·(1/2))/(25/48)
... P(box1 | blue) = 9/25 . . . . probability a blue ball is from box 1
The greatest common factor is the biggest thing that they all share... If we look at it they all have 4 as their coefficients so you can take that out but they also have a squared so you can take that out too so the GCF if 4a squared... but No x because one of them doesn't have it... all of them have to have it in common.
