Let f(x)=y
f^-1(x)=x
y=1/(x+5) - 1
y+1=1/(x+5)
(x+5)=1/(y+1)
x=1/(y+1)-5
f^-1(x)=1/(x+1) -5
denominator cannot equals to zero
x+1≠0
x≠-1
answer
B
Answer:
Yes. It is the simplest form as it cannot be simplified by any variables or values.
X=3
Let's solve your equation step-by-step.
−
|
x
−
4
|
+
2
=
−
2
x
+
7
Step 1: Add -2 to both sides.
−
|
x
−
4
|
+
2
+
−
2
=
−
2
x
+
7
+
−
2
−
|
x
−
4
|
=
−
2
x
+
5
Step 2: Divide both sides by -1.
−
|
x
−
4
|
−
1
=
−
2
x
+
5
−
1
|
x
−
4
|
=
2
x
−
5
Step 3: Solve Absolute Value.
|
x
−
4
|
=
2
x
−
5
We know either
x
−
4
=
2
x
−
5
or
x
−
4
=
−
(
2
x
−
5
)
x
−
4
=
2
x
−
5
(Possibility 1)
x
−
4
−
2
x
=
2
x
−
5
−
2
x
(Subtract 2x from both sides)
−
x
−
4
=
−
5
−
x
−
4
+
4
=
−
5
+
4
(Add 4 to both sides)
−
x
=
−
1
−
x
−
1
=
−
1
−
1
(Divide both sides by -1)
x
=
1
x
−
4
=
−
(
2
x
−
5
)
(Possibility 2)
x
−
4
=
−
2
x
+
5
(Simplify both sides of the equation)
x
−
4
+
2
x
=
−
2
x
+
5
+
2
x
(Add 2x to both sides)
3
x
−
4
=
5
3
x
−
4
+
4
=
5
+
4
(Add 4 to both sides)
3
x
=
9
3
x
3
=
9
3
(Divide both sides by 3)
x
=
3
Check answers. (Plug them in to make sure they work.)
x
=
1
(Doesn't work in original equation)
x
=
3
(Works in original equation)
