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Airida [17]
3 years ago
9

Adding which terms to 3x2y would result in a monomial? Check all that apply.

Mathematics
2 answers:
kkurt [141]3 years ago
8 0
 the answers are -12x^2 and 4x^2y. hopefully it helps and i just got it right.
velikii [3]3 years ago
5 0

Answer:

option 2 and 6

Step-by-step explanation:

Given : Monomial 3x^2y

To find : Adding which terms to  3x^2y would result in a monomial? Check all that apply.

Solution :

Monomial is when the number of terms is only 1.

1) 3xy

Adding in given monomial

3x^2y+3xy     is a binomial

2) -12x^2y

Adding in given monomial

3x^2y+(-12x^2y)=-9x^2y     is a monomial

3) 2x^2y^2

Adding in given monomial

3x^2y+2x^2y^2     is a binomial

4) 7xy^2

Adding in given monomial

3x^2y+7xy^2     is a binomial

5) -10x^2

Adding in given monomial

3x^2y-10x^2     is a binomial

6) 4x^2y

Adding in given monomial

3x^2y+4x^2y=7x^2y is a monomial

7) 3x^3

Adding in given monomial

3x^2y+3x^3     is a binomial

Therefore, Option 2 and 6 are the terms giving a monomial.

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aliina [53]

5x+7y=25

5x-2y=-65

subtract both of the equations

5x-5x=0

7y--2y= 7y+2y=9y

25--65=25+65=90

0+9y=90

9y=90

divide both sides by 9 to get y by itself

9y/9=90/9

cross out 9 and 9 which becomes 1*1*y=y

90/9=10

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find x by using the substitution method

5x+7y=25

5x+7(10)=25

5x+70=25

move +70 to the other side

sign changes from +70 to -70

5x+70-70=25-70

5x=-45

divide both sides by 5 to get x by itself

5x/5=-45/5

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x=-9

answer:

(-9,10)

6 0
3 years ago
How to put 7/13 in simplest form
Amiraneli [1.4K]

Answer: 7/13 is already in simplest form.

Step-by-step explanation:

The sides cannot both be divided by the same number, meaning it is already in simplest form.

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3 years ago
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PLEASE HELP!!!
goldfiish [28.3K]
The correct answer to the first question is: A'(-5, 6)



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miss Akunina [59]

Answer:

\left\{\begin{array}{l}y=-\dfrac{1}{9}x^2 +\dfrac{2}{9}x+\dfrac{89}{9}\\ \\y=\dfrac{1}{8}x^2 -7\end{array}\right.

Step-by-step explanation:

1st boat:

Parabola equation:

y=ax^2 +bx+c

The x-coordinate of the vertex:

x_v=-\dfrac{b}{2a}\Rightarrow -\dfrac{b}{2a}=1\\ \\b=-2a

Equation:

y=ax^2 -2ax+c

The y-coordinate of the vertex:

y_v=a\cdot 1^2-2a\cdot 1+c\Rightarrow a-2a+c=10\\ \\c-a=10

Parabola passes through the point (-8,1), so

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Parabola equation:

y=-\dfrac{1}{9}x^2 +\dfrac{2}{9}x+\dfrac{89}{9}

2nd boat:

Parabola equation:

y=ax^2 +bx+c

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y=ax^2+c

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Parabola passes through the point (-8,1), so

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Solve:

a=-\dfrac{1}{8}\\ \\b=0\\ \\c=-7

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y=\dfrac{1}{8}x^2 -7

System of two equations:

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