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Airida [17]
3 years ago
9

Adding which terms to 3x2y would result in a monomial? Check all that apply.

Mathematics
2 answers:
kkurt [141]3 years ago
8 0
 the answers are -12x^2 and 4x^2y. hopefully it helps and i just got it right.
velikii [3]3 years ago
5 0

Answer:

option 2 and 6

Step-by-step explanation:

Given : Monomial 3x^2y

To find : Adding which terms to  3x^2y would result in a monomial? Check all that apply.

Solution :

Monomial is when the number of terms is only 1.

1) 3xy

Adding in given monomial

3x^2y+3xy     is a binomial

2) -12x^2y

Adding in given monomial

3x^2y+(-12x^2y)=-9x^2y     is a monomial

3) 2x^2y^2

Adding in given monomial

3x^2y+2x^2y^2     is a binomial

4) 7xy^2

Adding in given monomial

3x^2y+7xy^2     is a binomial

5) -10x^2

Adding in given monomial

3x^2y-10x^2     is a binomial

6) 4x^2y

Adding in given monomial

3x^2y+4x^2y=7x^2y is a monomial

7) 3x^3

Adding in given monomial

3x^2y+3x^3     is a binomial

Therefore, Option 2 and 6 are the terms giving a monomial.

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State all integer values of x in the interval (-3, 3] that satisfy the following
Galina-37 [17]

(-3,3] is an interval which means that -3 and 3 are not inclusive of the values of x -5/3.

We have given

-3x+4 > 9

Required values of x.

State the values of x within -3 and 3.

subtract 4 from both sides,

-3x+4-4>9-4

<h3>What is the meaning of like terms?</h3>

like terms are terms that have the same variables and powers. The coefficients do not need to match.

Collect Like Terms

-3x > 5

(-3x)(-1)   <   5(-1)

3x  <  -5

Divide both sides by 3

3x/3 < -5/3

x    <   -5/3

(-3,3] is an interval which means that -3 and 3 are not inclusive of the values of x is -5/3.

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3 0
2 years ago
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4 0
3 years ago
Which of the following is the solution set of x² + 8x + 12 = 0?
raketka [301]

Answer:

\fbox{\begin{minipage}{9em}x = -2 and x = -6\end{minipage}}

Step-by-step explanation:

Given:

x^{2} + 8x + 12 = 0

Solve for:

x

Solution:

Step 1: Select the formula to solve for x

There are some ways to solve quadratic equations.

One of the simple way (if possible) is performing the factorization.

Another way is using the quadratic formula.

Here, we are going to use factorization.

Step 2: Perform factorization

      x^{2} + 8x + 12 = 0

<=>x^{2}  +  2x + 6x  + 12 = 0

<=>(x^{2} + 2x) + (6x + 12) = 0

<=>x(x + 2) + 6(x + 2) = 0

<=>(x + 2)(x + 6) = 0

<=> x = -2 or x = -6

Hope this helps!

:)

4 0
3 years ago
Evaluate the function found in the previous step at X =-3
babunello [35]
x-5y=-4x-2y

In order to evaluate the given function at x = -3, simply replace "x" in the function with -3 and solve.

-3-5y=-4(-3)-2y

<em>Multiply -4 and -3 in the function above.</em>

-3-5y=12-2y

<em>Add 3 on both sides of the equation.</em>

-3-5y+3=12-2y+3-5y=15-2y

<em>Add 2y on both sides of the equation.</em>

-5y+2y=15-2y+2y-3y=15

<em>Divide both sides of the equation by -3.</em>

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Therefore, at x = -3, the value of y = -5. Hence, f(-3) = -5.

Answer:

f(-3) = -5

<em />

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maxonik [38]

Answer:

A=12 B= 9

Step-by-step explanation:

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3 years ago
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