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Ivenika [448]
3 years ago
8

Prove the algebraic identity with the left hand side and supplying a sequence of equivalent expressions that ends with the right

hand side. X^3-x^2/x -(x-1)(x+1)=1-x
Mathematics
1 answer:
My name is Ann [436]3 years ago
4 0

Answer:

See Prove

Step-by-step explanation:

Given the expression: \dfrac{x^3-x^2}{x} -(x-1)(x+1)

To Prove: \dfrac{x^3-x^2}{x} -(x-1)(x+1)=1-x

Taking the Left-Hand side

\dfrac{x^3-x^2}{x} -(x-1)(x+1)\\=\dfrac{x(x^2-x)}{x} -[x(x+1)-1(x+1)]\\=x^2-x-[x^2+x-x-1]\\=x^2-x-x^2+1\\=-x+1\\=1-x

This is the right-hand side as required.

We have proved the given algebraic identity.

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