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hjlf
3 years ago
6

A bag contains 60 pieces of candy with different flavors: grape, strawberry, lemon, orange, apple, and watermelon. You want to r

un a simulation where you randomly draw one piece, replacing it each time, for 20 attempts. You decide to assign a number to represent the outcome of a specific flavor. Which range of values would you use to describe the outcomes?
Mathematics
2 answers:
White raven [17]3 years ago
6 0

Answer:

1-6

Step-by-step explanation:

gradpoint

a_sh-v [17]3 years ago
3 0

Answer:

We would use to describe numbers from 1 - 6.

Step-by-step explanation:

We represent the flavors as a set in Roster form.

F = {grape, strawberry, lemon, orange, apple, watermelon}

Note that that there are 6 flavors.

i.e., n(F) = 6

Since we have to assign a number for each flavor, and there are 6 flavors, we would use to describe numbers from 1 - 6.

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Rewrite 81 as 3 to some power.
NikAS [45]
First, let's find all the factors of 81:

81/3=27
27/3=9
9/3=3
3/1=1

So the factors of 81 are 3,3,3,3, (the numbers by which we divided here).

This means we can write down 81 as 3*3*3*3 or 3^{4} - which is the answer to the question! (three to the power of 4)
5 0
3 years ago
F(x)= 2x^3- x^2 +x+ 1 is divided by 2x +1.
ololo11 [35]

Answer:

Step-by-step explanation:

               x^2

           --------------------------------------------------

2x + 1  /  2x^3     -     x^2    +      x      +    1

               2x^3    +    x^2

              -----------------------

                                    0 + x + 1

                                        x + 1

The quotient is  x^2 + ------------

                                       2x + 1

8 0
3 years ago
75 is the median of the data set 68, 67, 75, 73, 72.
Ludmilka [50]
Truee is right you got it dude
4 0
2 years ago
Read 2 more answers
Product of 289 and 7
lyudmila [28]
Product means that u have to multiply the values so it will be 289*7 so it will be 2023
4 0
3 years ago
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"let v be the event that a computer contains a virus, and let w be the event that a computer contains a worm. suppose p(v) = 0.1
morpeh [17]

Here we might have to find p(v intersection w) and for that we use the following formula

p(v U w) = p(v)+p(w)-p(v intersection w)

And it is given that p(v) =01.3 , p(w) = 0.04 and p(v U w ) = 0.14 .

Substituting these values in the formula, we will get

0.14 = 0.13 +0.04 -p(v intersection w)

p(v intersection w) =0.13 +0.04 -0.14 = 0.03

So the required answer of the given question is 0.03 .

7 0
3 years ago
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