Answer: He actually rode 2 miles per hour on his trip
Step-by-step explanation: Maybe unconventional, but express the time it took, then figure the speed.
Time = distance /speed t will represent time, s is the speed: t = 30/s Use the rime it would have taken at the higher speed to create an equation:
t-12 = 30/s+8 replace the y with the 30/s
30/s -12 = 30/s+8
(s)(30/s -12 ) = (s)(30/s+8 ) Cross multiply to cancel denominators
(s-8)(30 -12s) = (s-8)(30s/s+8 ) ==> 30s +240 -12s² -96s =30s Simplify:
(-1)(-12s² -96s +240 ) =0 ==> 12s² +96s -240 divide all by 12
s² + 8s -20 = 0 Factor and solve for s
(s +10)(s -2) =0 s-2=0 S= 2
Proof:
30/2 = 15 hours for original trip at 2mph,
increase speed by 8mph 2 + 8 = 10mph
30 miles at 10mph takes 3 hours; that is 12 hours less than his actual trip.
(Brainilest, please :-)
Sorry but can we get a better shot of the paper can barley see it
Answer:
NO children. Because too many kids could make me stressed out. and I dont wanna be stressed out. I may be able to handle 1 or 2 kids but 12? nah imma be stressed and may think suici.d.e thoughts.
Step-by-step explanation:
Answser: first option <span>350(0.95)^x + 30x - 350
Explanation:
You can figure out the </span><span>function that shows the difference in price between option 1 and option 2 if you make a table simulating the behavior for a few months:
month price as per option 1 price as per option 2
start 350 350
1 350 - 5% (350) = 350 - 30
= 350 (0,95)
2 350 (0,95)×(0,95) =
350 (0,95)² 350 - 30(2)
3 350 (0,95)³ 350 - 30(3)
So now you can figure out the price with each option after x months:
350 (0.95)ˣ 350 - 30x
And the difference is 350 (0.95)ˣ - [350 - 30x]
Which, expanding the square brackets, is 350 (0.95)ˣ + 30x - 350 ↔ the first option.
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