\left[p \right] = \left[ -1.5 - 3.0\,t\right][p]=[−1.5−3.0t] is 3+2(2p+4t) equivalent
Answer:
The present age of son is 7
Step-by-step explanation:
Let the son age be x
One year ago
Son's age = x - 1
Therefore man's age = 8(x-1) =8x - 8
Now man's age = x^2
Difference between both ages if man =1 years
So
x^2 -(8x-8) = 1
x^2-8x + 8-1 =0
x^2- 8x + 7 = 0
x^2 - 7x -x + 7 = 0
X(x-7) - 7 ( x - 7) = 0
(x - 1) ( x - 7) = 0
x = 1, 7
But son cannot be 1 years
Therefore ,
x = 7
SO,
age of son is <em>7</em>
age of father is x×7=<em>49</em>
Its 100 because its not rounded to the nearest whole like 200 because its less than 50 so it would round down
Answer:
Step-by-step explanation:
first your going to do the least common multiple which is 12 for both then your going to subtract because were trying to find out how many students did there work correctly. so, whatever you do to the denominator you do to the numerator so, its going to be 10/12 - 9/12= 1/12 is your answer.
