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First, let's rewrite to make this problem easier.
1^2 - a^2b^2
Then we must multiply the terms with equal exponents with their bases.
1^2-(ab)^2
Using the factor: a^2 - b^2=(a-b)(a+b)
We can factor using that expression.
(1-ab) x (1+ab)
After factoring, this has been our solution.
Solution: (1-ab) x (1+ab)
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- Tutor John
Idk if it’s right but it gave me this answer
Answer:
So W is going to stand for width and L is going to stand for length.
L= 2W+6
78=2L + 2W
Those are the two equations you will use. So plug in L=2W+6 into the other one and solve.
78= 4W+12 +2W
(simplify)
78=6W+12
(-12 from both sides)
66=6W
(divide by 11)
W=11
Replug W into your equation to find L.
L=22+6
(simplify)
L=28
I hope this is right
Step-by-step explanation:
Answer:
D. -12,3,4,10
Step-by-step explanation:
Its D because the lines on the side of 4 and 3 means that it is the absolute value
Answer:
x=-4
Step-by-step explanation:
