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ale4655 [162]
3 years ago
15

a student claims that 8 to the third power times 8 to the -5 power is greater than 1 explain whether the student is correct or n

ot
Mathematics
1 answer:
nika2105 [10]3 years ago
7 0
I think he is not correct because there is negative number so it can't be greater than one
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Please help !!<br> idk math
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Answer:

Where's the question?

Step-by-step explanation:

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Anyone know how to do #21?
Andreas93 [3]
Would it be y2 ? idk im not sure but i tried


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3 years ago
How many terms do you have in the expression 7x - 2y + 8?
Westkost [7]

Answer:

3 terms we have constant ,Y and X terms

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1 year ago
I need the answer ASAP :( really struggling
pashok25 [27]
<h3>Answer: Choice A  -4 \le x \le -2</h3>

Explanation:

Ask yourself this: "When is the graph completely horizontally flat?" The answer to this question is when x is between -4 and -2. This is where the graph is constant. All other intervals are either increasing or decreasing.

Saying "The graph is constant" basically means "constant rate of change", which is another way of saying that the graph isn't changing. Constant means it stays the same.

So this is why the answer is -4 \le x \le -2

Note how only choice A has both endpoints in the negative region, so it is a quick way to spot the answer.

3 0
3 years ago
PLSSS HELP ASAP<br> solve questions 1-5 please
sertanlavr [38]

#1. 4x^2 + 17 - 15 = 0

Use the roots given, and plug them in to a factored form. Then, foil! It can also be helpful to multiply the equation to get rid of decimals/fractions.

(x - 3/4)(x + 5) = 0

x^2 - 3/4x + 5x - 3 3/4 = 0

x^2 + 4.25 - 3.75 = 0 (multiply everything by 4)

4x^2 + 17 - 15 = 0

#2. y = 0, -4

Both 4y^2 and 16y contain a 4 in the coefficient and a y in the variables. Therefore, we can factor out a 4y from each.

4y(y + 4) = 0

Then, set both parts of the factored equation equal to 0.

4y = 0

y = 0

y + 4 = 0

y = -4

#3. a = 0, -3

Both 6a^5 and 18a^4 contain a 6 in the coefficient and an a in the variables. Therefore, we can factor out a 6a^4 from each.

6a^4(a + 3) = 0

Then, set both parts of the factored equation equal to 0.

6a^4 = 0

a = 0

a + 3 = 0

a = -3

#4. x = -8

We are looking for two terms that multiply to equal a * c, and add up to equal b. We know that 8 + 8 = 16, and 8 * 8 = 64. There are no negatives in this equation, therefore both signs in our factored form are positive.

(x + 8)(x + 8) = 0

x + 8 = 0

x = -8

#5. x = -8, 8

First, subtract 64 from both sides. The key word here is 'factoring.' If this was not present, there is a different way (which may be easier for some).

x^2 = 64

x^2 - 64 = 0

Next, use the difference of two squares property to factor (x - c)(x + c), and set the two binomials equal to 0.

(x - 8)(x + 8) = 0

x - 8 = 0

x = 8

x + 8 = 0

x = -8

Hope this helps!! :)

3 0
3 years ago
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