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2 years ago

HELP ME PLEASE MATH Which graph represents the following system of inequalities?

Mathematics

1 answer:

Mekhanik [1.2K]2 years ago

8 0

y > 5x-1, because it is just a greater than sign, the shaded area would be to the left of a dotted line.

y ≤ x +3, because the sign is less than or equal to, the line is solid and the shaded area would be to the right.

Combine the shaded areas would make Graph B. the correct answer.

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Solve the system by substitution. 2x - y = -3, 2x-2y = -2

Sonja [21]

Answer:// Solve equation [1] for the variable y

[1] y = 2x - 3

// Plug this in for variable y in equation [2]

[2] -2•(2x-3) + 2x = 2

[2] - 2x = -4

// Solve equation [2] for the variable x

[2] 2x = 4

[2] x = 2

// By now we know this much :// Solve equation [1] for the variable y

[1] y = 2x - 3

// Plug this in for variable y in equation [2]

[2] -2•(2x-3) + 2x = 2

[2] - 2x = -4

// Solve equation [2] for the variable x

[2] 2x = 4

[2] x = 2

// By now we know this much :

y = 2x-3

x = 2

// Use the x value to solve for y

y = 2(2)-3 = 1

y = 2x-3

x = 2

// Use the x value to solve for y

y = 2(2)-3 = 1

Step-by-step explanation:

5 0

2 years ago

Can help me with math please and thank you

babunello [35]

Answer:

(0,0)

Step-by-step explanation:

They intersect at point (0,0)

4 0

2 years ago

Read 2 more answers

How do I differentiate this?

disa [49]

Answer:

$\frac{8}{\left(-x+2\right)^2}$ & $x = 1, x = 3$

Step-by-step explanation:

I'm sure you are familiar with the product rule,

If y = u*v => dy/dx = u * dv/dx + v * dy/dx <----- product rule

In this case:

$u=3x+2,\:v=\left(2-x\right)^{-1},\\=>\frac{d}{dx}\left(3x+2\right)\left(2-x\right)^{-1}+\frac{d}{dx}\left(\left(2-x\right)^{-1}\right)\left(3x+2\right)$

Now remember the sum rule:

$\frac{d}{dx}\left(3x+2\right) = \frac{d}{dx}\left(3x\right)+\frac{d}{dx}\left(2\right),\\\frac{d}{dx}\left(3x\right) = 3,\\\frac{d}{dx}\left(2\right) = 0\\\frac{d}{dx}\left(3x+2\right) = 3$

For this second bit we apply the chain rule:

$\frac{d}{dx}\left(\left(2-x\right)^{-1}\right) = -\frac{1}{\left(2-x\right)^2}\frac{d}{dx}\left(2-x\right),\\\frac{d}{dx}\left(2-x\right) = -1,\\\\=> -\frac{1}{\left(2-x\right)^2}\left(-1\right)\\=> \frac{1}{\left(2-x\right)^2}$

If we substitute these values back into the expression... $\frac{d}{dx}\left(3x+2\right)\left(2-x\right)^{-1}+\frac{d}{dx}\left(\left(2-x\right)^{-1}\right)\left(3x+2\right)$

...we get the following:

$3\left(2-x\right)^{-1}+\frac{1}{\left(2-x\right)^2}\left(3x+2\right)$

The rest is just pure simplification:

$3\left(2-x\right)^{-1}+\frac{1}{\left(2-x\right)^2}\left(3x+2\right)\\= \frac{3}{-x+2}+\frac{3x+2}{\left(-x+2\right)^2}\\= \frac{3\left(-x+2\right)}{\left(-x+2\right)^2}+\frac{3x+2}{\left(-x+2\right)^2}\\\\= \frac{3\left(-x+2\right)+3x+2}{\left(-x+2\right)^2}\\\\= \frac{8}{\left(-x+2\right)^2}$

Now let's equate this to equal 8 for the second bit and solve for x:

$\frac{8}{\left(-x+2\right)^2}=8,\\\frac{8}{\left(-x+2\right)^2}\left(-x+2\right)^2=8\left(-x+2\right)^2,\\8=8\left(-x+2\right)^2,\\\left(-x+2\right)^2=1,\\x = 1, x = 3$

4 0

2 years ago

If 5^2x=26, what is the value of x? x≈4.05 x≈1.41 x≈1.01 x≈0.99

babunello [35]

The correct answer is x≈1.01
You're welcome. ;)

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3 years ago

A cone has a volume of 226.08 cubic millimeters and a height of 6 millimeters. What is its

dezoksy [38]

Answer:

r≈5.36656314

Step-by-step explanation:

Since A=πr(r+ $\sqrt{h^2+r^2}$ ) so we get that 226.08/pi≈72 or 226.08/3.14=72 we then plug it in to get 72=r(r+ $\sqrt{36+r^2}$ ) so we get r≈5.36656314

6 0

3 years ago

Read 2 more answers