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3 years ago

What is the vertex of the graph of the function below?

Mathematics

1 answer:

inna [77]3 years ago

8 0

Answer:

D. (4, -4)

Step-by-step explanation:

Convert to vertex form by completing the square.

For a polynomial y = x² + bx + c, first add and subtract (b/2)² to the polynomial. Then factor.

Here, b = -8. So (b/2)² = (-8/2)² = 16.

y = x² − 8x + 12

y = x²− 8x + 16 − 16 + 12

y = (x − 4)² − 16 + 12

y = (x − 4)² − 4

The vertex is (4, -4).

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183.3 ÷ 0.78=????????????<br> Who ever answers 1st gets brainleist!!!

faust18 [17]

Answer:

235

Step-by-step explanation:

183.3 ÷ 0.78 = 235

This is due to the rules of division.

6 0

3 years ago

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3 years ago

Read 2 more answers

Simplify: cos2x-cos4 all over sin2x + sin 4x

GrogVix [38]

Answer:

$\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}=\tan\left(x\right)$

Step-by-step explanation:

$\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}$

Apply formula:

$\cos\left(A\right)-\cos\left(B\right)=-2\cdot\sin\left(\frac{A+B}{2}\right)\cdot\sin\left(\frac{A-B}{2}\right)$ and

$\sin\left(A\right)+\sin\left(B\right)=2\cdot\sin\left(\frac{A+B}{2}\right)\cdot\sin\left(\frac{A-B}{2}\right)$

We get:

$=\frac{-2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\sin\left(\frac{2x-4x}{2}\right)}{2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\cos\left(\frac{2x-4x}{2}\right)}$

$=\frac{-\sin\left(\frac{2x-4x}{2}\right)}{\cos\left(\frac{2x-4x}{2}\right)}$

$=\frac{-\sin\left(\frac{-2x}{2}\right)}{\cos\left(\frac{-2x}{2}\right)}$

$=\frac{-\sin\left(-x\right)}{\cos\left(-x\right)}$

$=\frac{-\cdot-\sin\left(x\right)}{\cos\left(x\right)}$

$=\frac{\sin\left(x\right)}{\cos\left(x\right)}$

$=\tan\left(x\right)$

Hence final answer is

$\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}=\tan\left(x\right)$

6 0

2 years ago

What is the length of segment AE?

nexus9112 [7]

Answer:

$AE=\frac{50}{3}\ units$

Step-by-step explanation:

step 1

In the right triangle ABC

Applying the Pythagoras Theorem fin the hypotenuse AC

$AC^{2} =AB^{2}+BC^{2}$

substitute

$AC^{2} =6^{2}+8^{2}$

$AC^{2} =100$

$AC =10\ units$

step 2

we know that

If two figures are similar, then the ratio of its corresponding sides is equal

$\frac{AB}{CD}=\frac{AC}{CE}$

substitute and solve for CE

$\frac{6}{4}=\frac{10}{CE}\\ \\CE=4*10/6\\ \\CE=\frac{20}{3}\ units$

step 3

Find the length of segment AE

AE=AC+CE

substitute the values

$AE=10\ units+\frac{20}{3}\ units=\frac{50}{3}\ units$

6 0

3 years ago

How do you know when to use the less than symbol and when to use the less than or equal to symbol when writing an inequality for

xenn [34]

Answer:

This depends on the situation. For context, you use less than when your inequality CANNOT exceed more than.

You would use less than or equal to if your inequality can be equal to a number. Here's an example.

John needs to buy X oranges and Y apples. He can AT MOST buy 10 total fruits.

x + y (equal to or less than) 45

John needs to buy X oranges and Y apples. He CANNOT buy more than 10 total fruits.

x + y < 45

5 0

3 years ago