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Ugo [173]
3 years ago
8

What is the vertex of the graph of the function below?

Mathematics
1 answer:
inna [77]3 years ago
8 0

Answer:

D. (4, -4)

Step-by-step explanation:

Convert to vertex form by completing the square.

For a polynomial y = x² + bx + c, first add and subtract (b/2)² to the polynomial.  Then factor.

Here, b = -8.  So (b/2)² = (-8/2)² = 16.

y = x² − 8x + 12

y = x²− 8x + 16 − 16 + 12

y = (x − 4)² − 16 + 12

y = (x − 4)² − 4

The vertex is (4, -4).

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Prove that the diagonals of a rhombus are perpendicular using coordinate geometry
lozanna [386]

If we draw a rhombus OABC on a coordinate grid with one vertex at the point O (0,0)

and let its height be 1 then (using the Pythagoras theorem) the coordinates of the 4 points will be as follows:-

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mihalych1998 [28]

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3 years ago
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Having a small brain moment, can you please help and show work
ankoles [38]

Answer:

The value if x is 0.9875.

Step-by-step explanation:

First, we have to get rid of brackets by expanding :

0.5(2x +  \frac{3}{4} ) -  \frac{1}{3} (0.1 + x) = 1

0.5(2x) + 0.5( \frac{3}{4} ) -  \frac{1}{3} (0.1) -  \frac{1}{3} (x) = 1

x +  \frac{3}{8}  -  \frac{1}{30}   -   \frac{1}{3} x = 1

Next you have to collect like terms :

x  -  \frac{1}{3} x +  \frac{3}{8}  -  \frac{1}{30}  = 1

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x =  \frac{79}{80}

x = 0.9875

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2 years ago
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