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3 years ago

How many ways can you arrange nine performers in a row on stage

1 answer:

7 0

Hey there !

No. of ways to arrange n objects is n!
[ When there's no conditions ]

Hence , number of ways we can arrange 9 performers is 9! = 362880 Ans.

Hope it helps!

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(-4,r) (-8,3) m=5 Find r please!

viva [34]

Answer:

r = 23

Step-by-step explanation:

m = (y2 - y1)/(x2 - x1)

5 = (3 - r)/(-8 - (-4))

5 = (3 - r)/(-8 + 4)

3 - r = 5 × -4

3 - r = -20

-r = -23

r = 23

4 0

3 years ago

If it continues to snow at the same rate, how many inches of snow would you expect after 6.5 hours? If you get stuck, you can us

ANTONII [103]

Answer:

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676494664jjxjduskqmwkwk

keieiebehidus

63434649496

jjdjsisi3343494966jssisusjsjs

Step-by-step explanation:

shhshshshshsisuwhsjsjjdjdjdososnhwjsjsjd

sjsjdjdjdjdjjdjdjdjdjdjdjdjdjdjdj

mdkdjdjdjdjdjjdjdjdjdj

djjdjdjdjd

djdjdjueiejehegdhdhdjjd

dsuduududhehh34346646464644

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5 0

3 years ago

Read 2 more answers

The graph of f is given in the figure to the right. Let A(x)equals=Integral from 0 to x f left parenthesis t right parenthesis

Tpy6a [65]

Answer:

$A(4)=-4\pi$

$A(8)=-4\pi +8$

$A(12)=-4\pi +16$

$A(14)=-4\pi +15$

Step-by-step explanation:

we are given

$A(x)=\int\limits^x_0 f{x} \, dx$

Calculation of A(4):

we can plug x=4

$A(4)=\int\limits^4_0 f{x} \, dx$

Since, this curve is below x-axis

so, the value of integral must be negative

and it is quarter of circle

so, we can find area of quarter circle

radius =4

$A(4)=-\frac{1}{4}\times \pi \times (4)^2$

$A(4)=-4\pi$

Calculation of A(8):

we can plug x=8

$A(8)=\int\limits^8_0 f{x} \, dx$

we can break into two parts

$A(8)=\int\limits^4_0 f{x} \, dx+\int\limits^8_4 f{x} \, dx$

now, we can find area and then combine them

$A(8)=-4\pi +\frac{1}{2}\times 4\times 4$

$A(8)=-4\pi +8$

Calculation of A(12):

we can plug x=12

$A(12)=\int\limits^12_0 f{x} \, dx$

we can break into two parts

$A(12)=\int\limits^4_0 f{x} \, dx+\int\limits^8_4 f{x} \, dx+\int\limits^12_8 f{x} \, dx$

now, we can find area and then combine them

$A(12)=-4\pi +\frac{1}{2}\times 8\times 4$

$A(12)=-4\pi +16$

Calculation of A(14):

we can plug x=14

$A(14)=\int\limits^14_0 f{x} \, dx$

we can break into two parts

$A(14)=\int\limits^4_0 f{x} \, dx+\int\limits^8_4 f{x} \, dx+\int\limits^12_8 f{x} \, dx+\int\limits^14_12 f{x} \, dx$

now, we can find area and then combine them

$A(14)=-4\pi +\frac{1}{2}\times 8\times 4-\frac{1}{2}\times 1\times 2$

$A(14)=-4\pi +16-1$

$A(14)=-4\pi +15$

8 0

3 years ago

Solve using elimination. 4x − 7y = 19 5x − 7y = 15

Likurg_2 [28]

Answer:

Point Form: (-4, -5)

Equation Form: x = -4, y = -5

Step-by-step explanation:

Add the equations in order to solve for the first variable. Plug this value into the other equations in order to solve for the remaining variables.

Brainliest Please!!!!!

- Hermionia

8 0

3 years ago

I need urgent help with this. please write out the working and the answer thank you

Lelechka [254]

1.   C = ⁵/₉F - 32
9C = 9(⁵/₉F - 32)
  9C = 9(⁵/₉F) - 9(32)
  9C = 5F - 288
- 5F - 5F
  9C - 5F = -288
- 9C   - 9C
-5F = -9C - 288
-5 -5
F = 1⁴/₅C + 57.6

2. $H = w + \frac{50}{m^{2}}$
   $m^{2}(H) = m^{2}(\frac{50}{m^{2}})$
   $Hm^{2} = 50$
   $\frac{Hm^{2}}{H} = \frac{50}{H}$
   $m^{2} = \frac{50}{H}$
   $\sqrt{m^{2}} = \sqrt{\frac{50}{H}}$
   $m = \frac{\sqrt{50}}{\sqrt{H}}$
   $m = \frac{5\sqrt{2}}{\sqrt{H}}$
   $m = \frac{5\sqrt{2}}{\sqrt{H}} * \frac{\sqrt{H}}{\sqrt{H}}$
   $m = \frac{5\sqrt{2H}}{H}$

3. A = 5 + 4√x
- 5 - 5
  A - 5 = 4√x
  (A - 5)² = (4√x)²
  A² - 10A + 25 = 16x
16 16
¹/₆A² - ⁵/₈A + 1⁹/₁₆ = x

4. $A = \frac{b + c}{b}$
   $Ab = b(\frac{b + c}{b})$
   $Ab = b + c$
   $Ab - b = c$
   $b(A) - b(1) = c$
   $b(A - 1) = c$
   $\frac{b(A - 1)}{A - 1} = \frac{c}{A - 1}$
   $b = \frac{c}{A - 1}$

3 0

3 years ago