Answer:
For number 2, its A. For number 1, its C.
Step-by-step explanation:
For both equations, you just set it equal to to each other because alternate interior angles are equivalent.
2) The equation would be
7x+3=6x+12
Then solve.
1) The equation would be
14x-3=95
Then solve.
I love geometry! If you have questions, just comment.
Let that be

Two vertical asymptotes at -1 and 0

If we simply

- Denominator has degree 2
- Numerator should have degree as 2 and coefficient as 3 inorder to get horizontal asymptote y=3 means the quadratic equation should contain 3x²
- But there should be a x intercept at -3 so one zeros should be -3
Find a equation
Find zeros
Horizontal asymptote
So our equation is

Graph attached
Answer:
y=a(x+4)^2 +1, for a real number a hat is different of 0.
Step-by-step explanation:
If we know only the vertex, there are many quandratic equations.
* Result: Vertex (m,n), the quadratic equation is y= a(x-m)^2 + n for a real number a that is different of 0.
Here, the vertex (-4,1), we have the equation: y=a(x+4)^2 +1, for a real number a hat is different of 0.
Hope you understand.
Answer:
Not quite sure what you're meant to solve for, but my solution is below.
Step-by-step explanation:
The square root of a value squared is the absolute value of that value, because squaring removes all negatives. Therefore:



Hope this helps!
Its probably a fraction.
You would know the answer if you researched what your question was on google