Step-by-step explanation:
4 and 5 is one 20/25
To solve this problem, let us recall that the formula for
probability is:
Probability = total number of successful events / total
events
Where in this case, an event is considered to be successful
if the sum is 3 on the pair of six sided dice.
First, let us calculate for the total number of events. There
are 6 numbers per dice, therefore the total number of combinations is:
total events = 6 * 6 = 36
Next, we calculate for the total number of combinations
that result in a sum of 3. We can identify that there are only two cases that
result in sum of 3. That is:
1st case: first dice rolls 1, second dice
rolls 2
2nd case: first dice rolls 2, second dice
rolls 1
Hence, total number of successful events = 2. Therefore the
probability is:
Probability = 2 / 36 = 1 / 18 = 0.0556 = 5.56%
First write what are given from the question
We write "<span>Craig scored 12 points in a game" as
</span>⇒ c = 12 <em>(first equation)</em>
We write "<span>Marla scored twice as many points as Craig but 5 fewer than Nelson scored" as
</span>⇒ m = 2c <em>(second equation)</em>
⇒ m = n - 5 <em>(third equation)</em>
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Second, find the expression for n based on what we write above
</span>From the second and third equation
⇒ m = m
⇒ n - 5 = 2c
Subtitute from the first equation
⇒ n - 5 = 2c
⇒ n - 5 = 2(12)
⇒ n - 5 = 24
This is the expression to find how many nelson scored
n - 5 = 24
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</span>
<span>You are given a card is picked from a standard deck of 52 cards. You are asked to determine the odds against and the odds in favor of selecting a 10. There are a total of 52 cards in a deck. In selecting a 10 of any card, you get four 10's in all kinds of cards (spade, clover, heart, diamond). So to solve for the probability of the odds in favor of selecting a 10, divide four by 52 and you get 10/52 or 5/26. To solve for the probability of the odds against selecting a 10, subtract four from 52 and you will get 48 and then divide it by 52 so 48/52 or 12/13. </span>
