What is the equation of a line that models wages with a slope of 15 that passes through the point (5, 90)?
1 answer:
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Basically, the parabola has to have all points that are equidistant from the focus and the directrix, the directrix being a horizontal line, and the focus being a point given. To derive an equation from this you need to use the distance formula which I'm guessing you already know because you're already in precalc.
The gist of it is that we have a random point on the parabola (x,y), and the point (x,y) will be equidistant from both the focus and the directrix. If we use the distance formula, you get something like this:
The square root of y-(-1/2) coming from the directrix, and the righthand side of the equal sign being derived from the focus.
All you need to do is simplify now!
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Hope I helped!
The gist of it is that we have a random point on the parabola (x,y), and the point (x,y) will be equidistant from both the focus and the directrix. If we use the distance formula, you get something like this:
The square root of y-(-1/2) coming from the directrix, and the righthand side of the equal sign being derived from the focus.
All you need to do is simplify now!
<span>
</span>
Hope I helped!
Answer:
18.84 estimated, 6π exactly
Step-by-step explanation:
Hi!
<u>The formula for finding the circumference of a circle is 2πr:</u>
In that case, all we need to do <em>first </em>is to divide the diameter by 2, so we can substitute that into the equation.
6 ÷ 2 = 3
So we have 2π × 3 to solve.
2π × 3 = 6π
We can estimate the circumference by multiplying by 3.14.
6 × 3.14 = 18.84
(actually multiplying by π gives 18.849... which is pretty close!)
Thus, the circumference is .
Hope this helps!