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4vir4ik [10]
3 years ago
14

A curb is 4 inches high. The ramp from the sidewalk yo the street follows the same guidelines as other Ramos (no more than 4.8 d

egrees, so a 1:12 ratio of vertical to horizontal). What is the horizontal distance for a ramp with a 4 inch vertical distance?
​
Mathematics
1 answer:
Effectus [21]3 years ago
4 0

Answer:

<h2>48 inches.</h2>

Step-by-step explanation:

Givens

  • The height of a curb is 4 inches. So, the ramp has a height of 4 inches.
  • The ratio between vertical and horizontal distance of the ramp is 1:12.

Accoriding to the given ration, one unit of vertical distance is equivalent to 12 units of horizontal distance. So, the horizontal distance is

h=12(4 \ in)=48 \ in

Therefore, the horizontal distance is 48 inches.

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Given: cosθ= -4/5 , sin x = -12/13 , θ is in the third quadrant, and x is in the fourth quadrant; evaluate tan 1/2 θ
mrs_skeptik [129]

Answer:

Step-by-step explanation:

If you're looking for what the half angle of the tangent of theta is, I'm a bit confused as to why you think the angle in the 4th quadrant, x, is relevant.  But maybe you don't know it isn't and it's a "trick" to throw you off.  Hmm...

Anyways, the half angle identity for tangent is

tan(\frac{\theta}{2})=\frac{sin\theta}{1+cos\theta}

There are actually 3 identities for the tangent of a half angle, but this one works just as well as either of the others do, so I'm going with this one.  

If theta is in QIII, the value of -4 goes along the x axis and the hypotenuse is 5.  That makes the missing side, by Pythagorean's Theorem, -3.  Filling in our formula:

tan(\frac{\theta}{2})=\frac{-\frac{3}{5} }{1+(-\frac{4}{5}) } which simplifies a bit to

tan(\frac{\theta}{2})=\frac{-\frac{3}{5} }{\frac{5}{5} -\frac{4}{5} }  and a bit more to

tan(\frac{\theta}{2})=\frac{-\frac{3}{5} }{\frac{1}{5} }

Bring up the lower fraction and flip it to divide to get

tan(\frac{\theta}{2})=-\frac{3}{5}*\frac{5}{1} which of course simplifies to

-3.  Choice A.

6 0
3 years ago
Please help!!! I have no idea why, but I can’t solve these problems!!!!
zaharov [31]
I don’t understand
5 0
3 years ago
the main rotor of a helicopter rotates 430 times per minute. find the number of degrees through which a point on the main rotor
n200080 [17]

Answer:

2580 degrees rotated per second

Step-by-step explanation:

since  you have to find the degrees it rotates per second.

you need to divide 430 by 60 to find rotations per second

1)          430/60

             =  7.16666667 rotations per second

-then you have to multiply it by 360 degrees ,because their is 360 degrees in a circle

2)        7.16666667 (360)

            =  2580 degrees rotated per second

6 0
3 years ago
(6x-3y - 12<br> - (2x+2y=10
madreJ [45]

Answer:

8x - 5y - 13

Step-by-step explanation:

(6x - 3y - 12) - (2x +2y - 10)

(6x - 3y - 12) - 2x - 2y + 10

6x - 3y - 23 - 2x - 2y + 10

8x - 5y - 13

8 0
3 years ago
Read 2 more answers
(question is on picture linked)
nalin [4]

here y+13=15

so we got y=2

then y+13+x+12=30

then we will get x=3

7 0
3 years ago
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