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4vir4ik [10]
3 years ago
14

A curb is 4 inches high. The ramp from the sidewalk yo the street follows the same guidelines as other Ramos (no more than 4.8 d

egrees, so a 1:12 ratio of vertical to horizontal). What is the horizontal distance for a ramp with a 4 inch vertical distance?
​
Mathematics
1 answer:
Effectus [21]3 years ago
4 0

Answer:

<h2>48 inches.</h2>

Step-by-step explanation:

Givens

  • The height of a curb is 4 inches. So, the ramp has a height of 4 inches.
  • The ratio between vertical and horizontal distance of the ramp is 1:12.

Accoriding to the given ration, one unit of vertical distance is equivalent to 12 units of horizontal distance. So, the horizontal distance is

h=12(4 \ in)=48 \ in

Therefore, the horizontal distance is 48 inches.

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-5 times h over 50 equal to -0.1 Solve h
shutvik [7]

Step-by-step explanation:

-5h/50 = -0.1

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3 years ago
The following table gives the scores of 30 students in a mathematics examination. Scores 90–99 80–89 70–79 60–69 50–59 Students
Pavel [41]
The given data is
Scores:      90-99  80-89  70-79  60-69  50-59
Students:   3          7           12        4          4
Because we are to take the middle value for each group.
Therefore the total score is
Sx = 3*94.5 + 7*84.5 + 12*74.5 + 4*64.5 + 4*54.5 = 2245
The number of students is 3+7+12+4+4 = 30

The mean is
m =2245/30 = 74.833

Calculate (Sx - m)² 
(Sx - m)² = 3*(94.5-74.833)² + 7*(84.5-74.833)² + 12*(64.5-74.833)²
               + 4*(64.5-74.833)² + 4*(54.5-74.833)² =  3896.7

Calculate the standard deviation
s = √(3896.7/29) = 11.592

Answer:
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std. deviation = 11.59
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3 years ago
Given right triangle ABC with altitude BD drawn to hypotenuse
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Answer:

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Step-by-step explanation:

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3 years ago
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