Answer:
11
Step-by-step explanation:
so we just make a system of equations:
x+y=36
say that x is the larger and y is the smaller
x-3=2y
so we can combine the equations and solve for x and y
re-arrange x-3=2y to be x=2y+3
x+y=36
x=2y+3
insert the value for x into x into x+y=36
2y+3+y=36
3y+3=36
y=11
now insert that back into x+y=36
11+x=36
x=25
Out of the two numbers x and y, 11 is the smaller number
Hope that helps :)
Hello,
The circle has like equation: (x+3)²+(y-2)²=r²
If x=1 then y=5 ==>(1+3)²+(5-2)²=r²==>4²+3²=r²==>r=5 (the radius)
if x=-7 then (-7+3)²+(y-2)²=25 ==> (y-2)²=25-16==>y=2+3 or y=2-3
The points (-7,5) and (-7,-1) are on the circle.
Remember you can' do anything to boht sides, but when times negative, flip sign
distributive property
a(b+c)=ab+ac
distribute the -4
-8+4x
now we have
2x<8-8+4x
2x<4x
minus 2x both sides
0<2x
therefor
0<x
answer is x>0
You show the text of the problem, but you need to show the figure too.