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Simora [160]
3 years ago
10

Six times a number is two hundred and forty what is The number

Mathematics
2 answers:
aniked [119]3 years ago
8 0
The number is 40. To solve this, all you have to do I'd divide 240 by 6 [240/6].
butalik [34]3 years ago
4 0
240/6=x
x=40

the number is 40
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Expand and simply x(2x + 3) + 5( x - 7)​
zalisa [80]

Answer:

2x² + 8x - 35

Step-by-step explanation:

x(2x + 3) + 5(x - 7) ← distribute both parenthesis

= 2x² + 3x + 5x - 35 ← collect like terms

= 2x² + 8x - 35

6 0
2 years ago
The image below is a triangle drawn inside a circle with center O: A triangle is shown inscribed inside a circle. The leg of the
Elis [28]

The area of a circle is given in terms of its radius by

 A = π · r²

Your circle has r=4 (half the diameter) and you want π=3.14. Using these values in the formula gives

 A = 3.14 · 4²

This matches your first selection

 3.14 · 4²

<em>                                              MARK AS BRAINLIEST</em>

7 0
3 years ago
Use rounding (to the nearest 10) to estimate the product of 3217 X 44.
Lorico [155]
So using whole number rounding I believe the answer you should get would be 141,550 as 3217 x 44 is equals to 141,548 so the answer may be 141,550 since 50 is the closest ten number to 48, with a distance of only 2 numbers.
8 0
3 years ago
What are the exact values of sin(2π3radians) and cos(2π3radians)
deff fn [24]
We know that
2π/3 radians-------> convert to degrees-----> 2*180/3---> 120°
120°=90°+30°

Part a) Find <span>sin(2π/3)
</span>sin(2π/3)=sin (90°+30°)
we know that
sin (A+B)=sin A*cos B+cos A*sin B
so
sin (90°+30°)=sin 90*cos 30+cos 90*sin 30
sin 90=1
cos 30=√3/2
cos 90=0
sin 30=1/2
sin (90°+30°)=1*√3/2+0*1/2-----> √3/2

the answer part a) is
sin(2π/3)=√3/2

Part b) Find cos (2π/3)
cos (2π/3)=cos (90°+30°)
we know that
cos (A+B)=cos A*cos B-sin A*sin B
so
cos (90°+30°)=cos 90*cos 30-sin 90*sin 30
sin 90=1
cos 30=√3/2
cos 90=0
sin 30=1/2
cos (90°+30°)=0*√3/2-1*1/2----> -1/2

the answer part b) is
cos (2π/3)=-1/2
8 0
3 years ago
A set of 9 numbers has a mean of 20. What additional number must be included in this set to create a new set with a mean that is
PIT_PIT [208]

<em>Greetings from Brasil...</em>

The average for a set of 9 elements will be

(A + B + C + D + E + F + G + H + I) ÷ 9 = 20

Let's make (A + B + C + D + E + F + G + H + I) like S

<em>(I chose S to remember a sum)</em>

Let us think.....

S ÷ 9 = 20

S = 20 × 9

S = 180

So,  (A + B + C + D + E + F + G + H + I) = 180

According to the statement, we will include a number (element J) in the sum to obtain a mean of (20 - 4), that is:

<h3>(A + B + C + D + E + F + G + H + I + J) ÷ 10 = (20 - 4)</h3>

as seen above, (A + B + C + D + E + F + G + H + I) = 180, then

(180 + J) ÷ 10 = 16

(180 + J) = 160

J = 160 - 180

<h2>J = - 20</h2><h2 />

So, including the number - 20 <em>(minus 20)</em> in the original mean we will obtain a new mean whose result will be 16

3 0
3 years ago
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