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2 years ago

Find the slope of the line that contains (−5,4) and (2,4).

Mathematics

1 answer:

klio [65]2 years ago

4 0

Answer:its a zero slope or you can do x2-x1 and y2-y1 and if its an even fraction try simplifying it .

Step-by-step explanation:

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Given: Two distinct circles that are tangent to each other at a common point. How many tangent lines can be drawn that touch bot

nika2105 [10]

there are only 3 tangent lines can be drawn that touch both circles

ok done. Thank to me :>

7 0

3 years ago

Is the table shown proportional? Explain

Sonja [21]

Yes, because the numbers are decreasing by the same amount every time.

5 0

3 years ago

Read 2 more answers

Convert 17,525,900 to words

Verizon [17]

Answer:

seventeen million five hundred and twenty-five thousand nine hundred

Step-by-step explanation:

3 0

4 years ago

In 2017 a pollution index was calculated for a sample of cities in the eastern states using data on air and water pollution. Ass

AlekseyPX

The percentage of cities with pollution index between 13.0 and 58.5 is 95%

Given that :

Mean = 35.9

Mean = 35.9Standard deviation = 11.6

The percentage of of the cities with pollution index between 13.0 and 58.5 points can be calculated thus :

Calculate the Zscore of both pollution index given :

Zscore = (x - mean) / standard deviation

x = raw score

For x = 13.0

Zscore = (13 - 35.9) / 11.6

Zscore = - 1.974

P(Z < - 1.974) = 0.024191

For x = 58.5

Zscore = (58.5 - 35.9) / 11.6

Zscore = - 1.948

P(Z < - 1.948) = 0.97429

The percentage of cities with pollution index between 13.0 and 58.5 :

P(Z < 1.948) - P(Z < - 1.974)

0.97429 - 0.024191 = 0.9500

0.9500 × 100 = 95%

Hence, The percentage of cities with pollution index between 13.0 and 58.5 is 95%

Learn more : Zscore : brainly.com/question/8165716

5 0

3 years ago

A common blood test performed on pregnant women to screen for chromosome abnormalities in the fetus measures the human chorionic

goldfiish [28.3K]

Answer:

(a) The proportion of women who are tested, get a negative test result is 0.82.

(b) The proportion of women who get a positive test result are actually carrying a fetus with a chromosome abnormality is 0.20.

Step-by-step explanation:

The Bayes' theorem states that the conditional probability of an event E $_{i}$ , of the sample space S, given that another event A has already occurred is:

$P(E_{i}|A)=\frac{P(A|E_{i})P(E_{i})}{\sum\liits^{n}_{i=1}{P(A|E_{i})P(E_{i})}}$

The law of total probability states that, if events E₁, E₂, E₃... are parts of a sample space then for any event A,

$P(A)=\sum\limits^{n}_{i=1}{P(A|B_{i})P(B_{i})}$

Denote the events as follows:

X = fetus have a chromosome abnormality.

Y = the test is positive

The information provided is:

$P(X)=0.04\\P(Y|X)=0.90\\P(Y^{c}|X^{c})=0.85$

Using the above the probabilities compute the remaining values as follows:

$P(X^{c})=1-P(X)=1-0.04=0.96$

$P(Y^{c}|X)=1-P(Y|X)=1-0.90=0.10$

$P(Y|X^{c})=1-P(Y^{c}|X^{c})=1-0.85=0.15$

(a)

Compute the probability of women who are tested negative as follows:

Use the law of total probability:

$P(Y^{c})=P(Y^{c}|X)P(X)+P(Y^{c}|X^{c})P(X^{c})$

$=(0.10\times 0.04)+(0.85\times 0.96)\\=0.004+0.816\\=0.82$

Thus, the proportion of women who are tested, get a negative test result is 0.82.

(b)

Compute the value of P (X|Y) as follows:

Use the Bayes' theorem:

$P(X|Y)=\frac{P(Y|X)P(X)}{P(Y|X)P(X)+P(Y|X^{c})P(X^{c})}$

$=\frac{(0.90\times 0.04)}{(0.90\times 0.04)+(0.15\times 0.96)}$

$=0.20$

Thus, the proportion of women who get a positive test result are actually carrying a fetus with a chromosome abnormality is 0.20.

6 0

4 years ago