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3 years ago

What is the atmospheric pressure of the U.S.

1 answer:

4 0

When you say atmospheric pressure it is a standard on all places on earth. The value of standard atmospheric pressure is 1 Bar approximately or 14.7 lb per square inch. This pressure is an attribute of free molecules on the air which is not bound the accumulation of the pressure of this in average is the atmospheric pressure.

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A car traveling at 31 m/s starts to decelerate steadily. It comes to a complete stop in 7 seconds. What is its acceleration

N76 [4]

Vf=V1+at
0=31+a(7)
-31/7=a
a=-4.43m/s^2

Hope this helps.

8 0

3 years ago

there are 5 influencing factors that may affect participation rate in physical activity. can you name them?

Stella [2.4K]

Demographic Barriers, Occupation, Age, Obesity, <span>
Psychological Barriers</span>

6 0

4 years ago

Assume that the energy lost was entirely due to friction and that the total length of the PVC pipe is 1 meter. Use this length t

gladu [14]

The question is incomplete. The complete question is :

Assume that the energy lost was entirely due to friction and that the total length of the PVC pipe is 1 meter. Use this length to compute the average force of friction (for this calculation, you may neglect uncertainties).

Mass of the ball : 16.3 g

Predicted range : 0.3503 m

Actual range : 1.09 m

Solution :

Given that :

The predicted range is 0.3503 m

Time of the fall is :

$t=\sqrt{\frac{2H}{g}}$

$v_1t= 0.35$ ...........(i)

$v_0t= 1.09$ ...........(ii)

Dividing the equation (ii) by (i)

$\frac{v_0t}{v_1t}=\frac{1.09}{035} = 3.11$

∴ $v_0=3.11 \ v_1$

Now loss of energy = change in the kinetic energy

$W=\frac{1}{2} m [v_0^2-v_1^2]$

$W=\frac{1}{2} \times (16.3 \times 10^{-3}) \times [v_0^2-\left(\frac{v_0}{3.11}\right)^2]$

$W=7.307\times 10^{-3} \ v_0^2$

If f is average friction force, then

(f)(L) = W

(f) (1) = $7.307\times 10^{-3} \ v_0^2$

(f) = $7.307\times 10^{-3} \ v_0^2$

3 0

3 years ago

A 25.0 kg object is held 8.50 m above the ground. Calculate its PE

pantera1 [17]

Answer:=mgh

Explanation:

6 0

3 years ago

What would the density of an object be with a mass of 0.8g

True [87]

The density of the object is 0.032 g/cm^3.

<h3>What is density?</h3>

The term density means the ratio of the mass to the volume of an object. Now we know that when an object is dense that it would sink to the bottom of a fluid.

Now given that;

Mass = 0.8 g

volume= 25 cm^3

Density = mass/volume

Density = 0.8 g / 25 cm^3

= 0.032 g/cm^3

Learn more about density:brainly.com/question/15164682

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MISSING PARTS

What is the density of an object having a mass of

0.8g and a volume of 25cm^3

4 0

2 years ago