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Nesterboy [21]
3 years ago
15

The diagram below represents a structure in the cell

Physics
1 answer:
dusya [7]3 years ago
8 0
It might be CO2 but I’m not sure since I haven’t learned this since 5th grade
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PLS HELP MEEEE (NO LINKS PLEASE)
-Dominant- [34]
I think it could be D please tell me if I’m wrong I hope you have a wonderful day ❤️
5 0
2 years ago
Read 2 more answers
A thin, flat washer is a disk with an outer diameter of 14 cm and a hole in the center with a diameter of 7 cm. The washer has a
Kryger [21]

Answer:

2583.9 N/C

Explanation:

Parameters given:

Outer diameter = 14 cm

Outer radius, R = 7cm = 0.07m

Inner diameter = 7 cm

Inner radius, r = 3.5 cm = 0.035m

Charge of washer = 8 nC = 8 * 10^(-9)C

Distance from washer, z = 33 cm = 0.33m

The electric field due to a washer (hollow disk) is given as:

E = k * σ * 2π [ 1 - z/(√(z² + R²)]

Where σ = charge per unit area

σ = q/π(R² - r²)

σ = 8 * 10^(-9) /(π*(0.07 - 0.035)²)

σ = 2.077 * 10^(-6) C/m²

=> E = 9 * 10^9 * 2.077 * 10^(-6) * 2π * [1 - 0.33/(√(0.33² + 0.07²)]

E = 117.467 * 10^3 * (1 - 0.978)

E = 117.467 * 10^3 * 0.022

E = 2583.9 N/C

6 0
3 years ago
When flying the LNAV approach, the missed approach point (MAP) would be indicated by reaching __________. A. an altitude of 3100
frutty [35]

Answer:

When flying the LNAV Approach, the missed approach point (MAP) would be indicated by reaching:

C. the RW30 waypoint.

Explanation:

  • In Aviation, LNAV stands for Lateral Navigation. The option a is incorrect as an altitude of 3100 feet refers to the decision altitude not the missed approach point.
  • The option b is incorrect as a distance of 1.5 NM  to RW30 referring to the Visual descent point (VDP) is 1.5 nautical miles for the Runway (RW) 30 from threshold.
  • The option c is correct as Missed approach point is designed to coincide with the runway threshold. The RW 30 way point is referring to the way point to the threshold for the Runway 30.

8 0
3 years ago
PLZ HELP MEEEEEEEEE ASAP
mafiozo [28]
The answer is “Impulse acting on it” according to the impulse-momentum theorem.
6 0
2 years ago
A rigid adiabatic container is divided into two parts containing n1 and n2 mole of ideal gases respectively, by a movable and th
kicyunya [14]

Answer:

Explanation:

Given

Pressure, Temperature, Volume of gases is

P_1, V_1, T_1 & P_2, V_2, T_2

Let P & T be the final Pressure and Temperature

as it is rigid adiabatic container  therefore Q=0 as heat loss by one gas is equal to heat gain by another gas

-Q=W+U_1----1

Q=-W+U_2-----2

where Q=heat loss or gain (- heat loss,+heat gain)

W=work done by gas

U_1 & U_2 change in internal Energy of gas

Thus from 1 & 2 we can say that

U_1+U_2=0

n_1c_v(T-T_1)+n_2c_v(T-T_2)=0

T(n_1+n_2)=n_1T_1+n_2T_2

T=\frac{n_1+T_1+n_2T_2}{n_1+n_2}

where n_1=\frac{P_1V_1}{RT_1}

n_2=\frac{P_2V_2}{RT_2}

T=\frac{\frac{P_1V_1}{RT_1}\times T_1+\frac{P_2V_2}{RT_2}\times T_2}{\frac{P_1V_1}{RT_1}+\frac{P_2V_2}{RT_2}}

T=\frac{P_1V_1+P_2V_2}{\frac{P_1V_1}{T_1}+\frac{P_2V_2}{T_2}}

and P=\frac{P_1V_1+P_2V_2}{V_1+V_2}

6 0
3 years ago
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