To develop this problem it is necessary to apply the concepts related to the angular resolution of a telescope as well as to the arc length.
The arc length can be defined as
![s = r\theta](https://tex.z-dn.net/?f=s%20%3D%20r%5Ctheta)
Where
r= Radius
\theta = Angle
At the same time the angular resolution of a body is given under the proportion
![\theta = 1.22\frac{\lambda}{D}](https://tex.z-dn.net/?f=%5Ctheta%20%3D%201.22%5Cfrac%7B%5Clambda%7D%7BD%7D)
Where
= Wavelength
D = Diameter
Our values are given as
![\lambda = 550*10^{-9}m](https://tex.z-dn.net/?f=%5Clambda%20%3D%20550%2A10%5E%7B-9%7Dm)
![D = 6.5m](https://tex.z-dn.net/?f=D%20%3D%206.5m)
![r = 3.82*10^5Km = 3.82*10^8m](https://tex.z-dn.net/?f=r%20%3D%203.82%2A10%5E5Km%20%3D%203.82%2A10%5E8m)
Then the angle of separation of the two objects seen from the observer is of
![\theta = 1.22 \frac{550*10^{-9}}{6.5}](https://tex.z-dn.net/?f=%5Ctheta%20%3D%201.22%20%5Cfrac%7B550%2A10%5E%7B-9%7D%7D%7B6.5%7D)
![\theta = 1.032*10^{-7}](https://tex.z-dn.net/?f=%5Ctheta%20%3D%201.032%2A10%5E%7B-7%7D)
Finally, using the proportion of the arc length, in which we have the radius and angle we can know the separation of the two objects by:
![s = (3.82*10^8)(1.032*10^{-7})](https://tex.z-dn.net/?f=s%20%3D%20%283.82%2A10%5E8%29%281.032%2A10%5E%7B-7%7D%29)
![s = 39.43m](https://tex.z-dn.net/?f=s%20%3D%2039.43m)
No. The correct one would be D .
Answer:
Its new current will be 240.0milliAmps
Explanation:
According to ohms law,
V = IR
V is the supply voltage in a circuit
I is the current
R is the resistance
If the current in the wires of a circuit is 120.0 milliAmps, the voltage will be:
V1 = 120R1
R1 = V1/120...(1)
If the voltage impressed across the ends of the circuit were doubled (with no change in its resistance),
V2 = 2V1
V2 = IR2
2V1 = IR2
R2 = 2V1/I ... (2)
Since there are no changes in resistance
R1 = R2
Equating 1 and 2, we have:
V1/120 = 2V1/I
1/120 = 2/I
Cross multiplying
I = 2×120
I = 240milliAmps
Explanation:
F=(Gmm)/(r^2)
larger the mass stronger the force. An object with a large mass will produce a large force. A small mass will produce a small force.
Answer: <u><em>2.03259656 × 10^8</em></u>
Explanation:
1.5 x 10 = 15
√(15) = <em>3.87</em>
<u><em>put this to the side until we sum everything up..</em></u>
3.5 × 10 = 35
35 ^ 5 = <em>52521875</em>
So, now lets sum it all up....
(3.87) x (52521875) = <u><em>203259656.25</em></u>
but in scientific notation it is: <u><em>2.03259656 × 10^8</em></u>
<u><em>If helpful, please mark as brainliest! =)</em></u>