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ahrayia [7]
3 years ago
7

I don't know why it is faced that way but help plz

Mathematics
2 answers:
Nady [450]3 years ago
7 0

Answer: x > 5

Step-by-step explanation: You need to isolate x. First, distribute the 1/2 into the parentheses. You will get:

4x + x + 2 > 12

Combine like terms.

5x + 2 > 12

Subtract 2 from each side.

5x > 10

Divide by 5 on each side.

X > 2

Since x is by itself, that is the answer.

mr_godi [17]3 years ago
7 0

Answer:

x > 2

Step-by-step explanation:

<u>Distribute 1/2</u>

Distribute 1/2 inside the parentheses

1/2 * 2x = x

1/2 * 4 = 2

<u>Simplify</u>

4x + x + 2 > 12

<u>Combine like terms</u>

5x + 2 > 12

<u>Subtract 2 in both sides</u>

2 - 2 = 0

12 - 2 = 10

5x > 10

<u>Divide 5 in both sides</u>

5x/5 = x

10/5 = 2

<u>Simplify</u>

x > 2

<u>Answer</u>

x > 2

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Instructions:Select the correct answer from each drop-down menu. ∆ABC has vertices at A(11, 6), B(5, 6), and C(5, 17). ∆XYZ has
Akimi4 [234]

to compare the triangles, first we will determine the distances of each side

<span>Distance = ((x2-x1)^2+(y2-y1)^2)^0.5
</span>Solving 

<span>∆ABC  A(11, 6), B(5, 6), and C(5, 17)</span>

<span>AB = 6 units   BC = 11 units AC = 12.53 units
</span><span>∆XYZ  X(-10, 5), Y(-12, -2), and Z(-4, 15)
</span><span>XY = 7.14 units   YZ = 18.79 units XZ = 11.66 units</span>

<span>∆MNO  M(-9, -4), N(-3, -4), and O(-3, -15).</span>

<span>MN = 6 units   NO = 11 units MO = 12.53 units
</span><span>∆JKL  J(17, -2), K(12, -2), and L(12, 7).
</span><span>JK = 5 units   KL = 9 units JL = 10.30 units
</span><span>∆PQR  P(12, 3), Q(12, -2), and R(3, -2)
</span><span>PQ = 5 units   QR = 9 units PR = 10.30 units</span> 
Therefore
<span>we have the <span>∆ABC   and the </span><span>∆MNO  </span><span> 
with all three sides equal</span> ---------> are congruent  
</span><span>we have the <span>∆JKL  </span>and the <span>∆PQR 
</span>with all three sides equal ---------> are congruent  </span>

 let's check

 Two plane figures are congruent if and only if one can be obtained from the other by a sequence of rigid motions (that is, by a sequence of reflections, translations, and/or rotations).

 1)     If ∆MNO   ---- by a sequence of reflections and translation --- It can be obtained ------->∆ABC 

<span> then </span>∆MNO<span> ≅</span> <span>∆ABC  </span> 

 a)      Reflexion (x axis)

The coordinate notation for the Reflexion is (x,y)---- >(x,-y)

<span>∆MNO  M(-9, -4), N(-3, -4), and O(-3, -15).</span>

<span>M(-9, -4)----------------->  M1(-9,4)</span>

N(-3, -4)------------------ > N1(-3,4)

O(-3,-15)----------------- > O1(-3,15)

 b)      Reflexion (y axis)

The coordinate notation for the Reflexion is (x,y)---- >(-x,y)

<span>∆M1N1O1  M1(-9, 4), N1(-3, 4), and O1(-3, 15).</span>

<span>M1(-9, -4)----------------->  M2(9,4)</span>

N1(-3, -4)------------------ > N2(3,4)

O1(-3,-15)----------------- > O2(3,15)

 c)   Translation

The coordinate notation for the Translation is (x,y)---- >(x+2,y+2)

<span>∆M2N2O2  M2(9,4), N2(3,4), and O2(3, 15).</span>

<span>M2(9, 4)----------------->  M3(11,6)=A</span>

N2(3,4)------------------ > N3(5,6)=B

O2(3,15)----------------- > O3(5,17)=C

<span>∆ABC  A(11, 6), B(5, 6), and C(5, 17)</span>

 ∆MNO  reflection------- >  ∆M1N1O1  reflection---- > ∆M2N2O2  translation -- --> ∆M3N3O3 

 The ∆M3N3O3=∆ABC 

<span>Therefore ∆MNO ≅ <span>∆ABC   - > </span>check list</span>

 2)     If ∆JKL  -- by a sequence of rotation and translation--- It can be obtained ----->∆PQR 

<span> then </span>∆JKL ≅ <span>∆PQR  </span> 

 d)     Rotation 90 degree anticlockwise

The coordinate notation for the Rotation is (x,y)---- >(-y, x)

<span>∆JKL  J(17, -2), K(12, -2), and L(12, 7).</span>

<span>J(17, -2)----------------->  J1(2,17)</span>

K(12, -2)------------------ > K1(2,12)

L(12,7)----------------- > L1(-7,12)

 e)      translation

The coordinate notation for the translation is (x,y)---- >(x+10,y-14)

<span>∆J1K1L1  J1(2, 17), K1(2, 12), and L1(-7, 12).</span>

<span>J1(2, 17)----------------->  J2(12,3)=P</span>

K1(2, 12)------------------ > K2(12,-2)=Q

L1(-7, 12)----------------- > L2(3,-2)=R

 ∆PQR  P(12, 3), Q(12, -2), and R(3, -2)

 ∆JKL  rotation------- >  ∆J1K1L1  translation -- --> ∆J2K2L2=∆PQR 

<span>Therefore ∆JKL ≅ <span>∆PQR   - > </span><span>check list</span></span>
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3 years ago
What is the equation of a parabola in vertex form for a line that passed through (5,-4) and has vertex (-2,5)
Ahat [919]

\text{The vertex form of a parabola}\\\\y=a(x-h)^2+k\\\\\text{We have the vertex}\ (-2,\ 5)\to h=-2,\ k=5.\\\\\text{Substitute}\\\\y=a(x-(-2))^2+5=a(x+2)^2+5\\\\\text{We have the point}\ (5,\ -4).\\\text{Substitute the coordinates of the point to the equation:}\\\\-4=a(5+2)^2+5\\\\-4=a(7)^2+5\\\\-4=49a+5\qquad|-5\\\\-9=49a\qquad|:49\\\\a=-\dfrac{9}{49}\\\\Answer:\ \boxed{y=-\dfrac{9}{49}(x+2)^2+5}

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5(x+3)=2x+3 what is x?
kvasek [131]

Answer:

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2 years ago
Read 2 more answers
Ricardo has a square hot tub. He wants to build a square pool next to it that is a dilation of the hot tub using a scale factor
ozzi

Answer:

\boxed{Side \ Length \ of \ hot \ tub = 4.8\ ft.}

Step-by-step explanation:

Scale Factor = 5

Also,

B'C' = 24 feet

Since both are squares so both have all sides equal.

Sqaure A'B'C'D' is dilated by a scale factor of 5

So,

AB = BC = CD = DA = 24/5 = 4.8 ft.

4 0
3 years ago
Answer all please.....^
postnew [5]
#4) 1/6
#5) 1/2
#6) 4/15
#7) 8/15
#8) 11/15
#9) 12
#10) 15
#11) 112

Explanation
#4) There is one section marked 5 out of 6 sections.

#5) There are three odd-numbered sections out of 6 sections.

#6) 2 blue were tossed 4 times out of 15 tosses.

#7) 1 blue and 1 pink were tossed 8 ties out of 15 tosses.

#8) All blue was tossed 4 times out of 15; this means that all blue was not tossed 15-4=11 times out of 15.

#9) There are 4 choices for location and 3 choices for transportation; 4(3) = 12.

#10) There are 3 choices for level and 5 choices for character; 3(5) = 15.

#11) Since 30% are rock, 100%-30% = 70% are not rock.  70% = 70/100 = 0.7; 0.7*160 = 112.
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3 years ago
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