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3 years ago

Factor the following trinomial. 2x^2+12x+16

Mathematics

2 answers:

laila [671]3 years ago

6 0

My answer was 2 x^2 +12x +18

kobusy [5.1K]3 years ago

3 0

(2x + 8) (x+2) is what I got

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Simplify ( √ 5 ) ( 3 √ 5 )

Amiraneli [1.4K]

Answer:

$5^\frac{5}{6}$

Step-by-step explanation:

$\sqrt{5}$ can be represented as $5^{\frac{1}{2}}$ and $\sqrt[3]5}$ can be represented as $5^{\frac{1}{3}}$ . Therefore, the expression can be rewritten as:

$5^{\frac{1}{2}}*5^{\frac{1}{3}}$

The rule for multiplying two exponents with the same base is you add the exponents. For example: $x^m*x^k=x^{m+k}$

We can use the same property to get:

$5^{\frac{1}{2} +\frac{1}{3}}$

which is just $5^\frac{5}{6}$ after you add the fractions

8 0

3 years ago

Your uncle is currently four times as old as you are. In five years, your uncle will be three times as old as you. What is your

sertanlavr [38]

Answer:

your uncle will always be 4 times as old as you if he is currently 4 times as old as you

Step-by-step explanation:

kinda self explanatory so i think its a trick question haha

8 0

2 years ago

0.125,0.25,0.5,1 sequence

stiv31 [10]

Answer:

1,2,4,8,16,32

Step-by-step explanation:

power of two sequence

5 0

3 years ago

How to find the vertex calculus 2What is the vertex, focus and directrix of x^2 = 6y

son4ous [18]

Solution:

Given:

$x^2=6y$

Part A:

The vertex of an up-down facing parabola of the form;

$\begin{gathered} y=ax^2+bx+c \\ is \\ x_v=-\frac{b}{2a} \end{gathered}$

Rewriting the equation given;

$\begin{gathered} 6y=x^2 \\ y=\frac{1}{6}x^2 \\ \\ \text{Hence,} \\ a=\frac{1}{6} \\ b=0 \\ c=0 \\ \\ \text{Hence,} \\ x_v=-\frac{b}{2a} \\ x_v=-\frac{0}{2(\frac{1}{6})} \\ x_v=0 \\ \\ _{} \\ \text{Substituting the value of x into y,} \\ y=\frac{1}{6}x^2 \\ y_v=\frac{1}{6}(0^2) \\ y_v=0 \\ \\ \text{Hence, the vertex is;} \\ (x_v,y_v)=(h,k)=(0,0) \end{gathered}$

Therefore, the vertex is (0,0)

Part B:

A parabola is the locus of points such that the distance to a point (the focus) equals the distance to a line (directrix)

Using the standard equation of a parabola;

$\begin{gathered} 4p(y-k)=(x-h)^2 \\ \\ \text{Where;} \\ (h,k)\text{ is the vertex} \\ |p|\text{ is the focal length} \end{gathered}$

Rewriting the equation in standard form,

$\begin{gathered} x^2=6y \\ 6y=x^2 \\ 4(\frac{3}{2})(y-k)=(x-h)^2 \\ \text{putting (h,k)=(0,0)} \\ 4(\frac{3}{2})(y-0)=(x-0)^2 \\ Comparing\text{to the standard form;} \\ p=\frac{3}{2} \end{gathered}$

Since the parabola is symmetric around the y-axis, the focus is a distance p from the center (0,0)

Hence,

$\begin{gathered} Focus\text{ is;} \\ (0,0+p) \\ =(0,0+\frac{3}{2}) \\ =(0,\frac{3}{2}) \end{gathered}$

Therefore, the focus is;

$(0,\frac{3}{2})$

Part C:

A parabola is the locus of points such that the distance to a point (the focus) equals the distance to a line (directrix)

Using the standard equation of a parabola;

$\begin{gathered} 4p(y-k)=(x-h)^2 \\ \\ \text{Where;} \\ (h,k)\text{ is the vertex} \\ |p|\text{ is the focal length} \end{gathered}$

Rewriting the equation in standard form,

Since the parabola is symmetric around the y-axis, the directrix is a line parallel to the x-axis at a distance p from the center (0,0).

Hence,

$\begin{gathered} Directrix\text{ is;} \\ y=0-p \\ y=0-\frac{3}{2} \\ y=-\frac{3}{2} \end{gathered}$

Therefore, the directrix is;

$y=-\frac{3}{2}$

3 0

1 year ago

Find the HEIGHT of the rectangular prism given its surface area is 238 square yards.

o-na [289]

Answer:

Height = 5

Step-by-step explanation:

7 0

3 years ago