Question

Mark is creating a tarp to cover his new vegetable garden outside. He needs enough nylon to cover the garden which is 10 feet by 8 feet and then he will attach rope along the edges of the nylon to stake it down with. He goes to the store and the nylon costs $5.25 a square yard and the rope is $1.25 a foot. How much will it cost him to make the cover?

Answer 1

Answer:

$91.67.

Step-by-step explanation:  

We have been given that Mark is creating a tarp to cover his new vegetable garden outside. He needs enough nylon to cover the garden which is 10 feet by 8 feet and then he will attach rope along the edges of the nylon to stake it down with.

A. Let us find area covered by nylon by multiplying 10 by 8.

$\text{ Amount of Nylon needed to cover the garden}=10\text{ feet}*8\text{ feet}$

$\text{ Amount of Nylon needed to cover the garden}=80\text{ feet}^{2}$

Now let us convert area of needed nylon from square feet into square yard by multiplying 80 by 0.111111.

$\text{ Amount of Nylon needed to cover the garden}=80*0.111111\text{ yards}^{2}$

$\text{ Amount of Nylon needed to cover the garden}=8.88889\text{ yards}^{2}$

Now let us multiply 8.88889 by 5.25 to find the cost of nylon cover of the garden.

$\text{ Cost of Nylon cover of the garden}=8.88889*5.25$

$\text{ Cost of Nylon cover of the garden}=46.6666725\approx 46.67$

Therefore, the cost of nylon cover will be $46.67.

B. Now let us find length of rope by finding the perimeter of the garden.

$\text{Length of rope}=2(10+8)\text{ feet}$

$\text{Length of rope}=2(18)\text{ feet}$

$\text{Length of rope}=36\text{ feet}$

Now let us find the cost of 36 feet long rope by multiplying 36 by 1.25.

$\text{Cost of rope}=36*1.25$

$\text{Cost of rope}=45$

Therefore, the cost of rope will be $45.

To find the total cost to make the cover we will add cost of nylon cover and cost of rope.

$\text{Total cost to make the cover}=45+46.67$

$\text{Total cost to make the cover}=91.67$

Therefore, it will cost $91.67 for Mark to make the cover for vegetable garden.