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2 years ago

Which statements are true? Check all that apply.

Mathematics

1 answer:

Aleksandr-060686 [28]2 years ago

7 0

Answer:

um ok i do not know

Step-by-step explanation:

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Answer: B seems to be the correct one

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3 years ago

Here are 30 best lifetime baseball batting averages of all time is shown to the right. These data can be graphically displayed a

Alex

Answer:

B). Graph B

Step-by-step explanation:

A Histogram is a graphic representation of data using bars varying in height as per the range of values.

In the given question, the second option correctly represents the data provided in the table using a histogram. It portrays the class ranging from 0.320 - 0.329 with an average of 1 in the first bar, from 0.330 - 0.339 with an average of 14 runs in the second bar, and moves so on till 0.360-0.369 correctly. The other options fail to portray the numerical distribution appropriately and hence, option B is the correct answer.

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3 years ago

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2 years ago

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A professor wishes to discover if seniors skip more classes than freshmen. Suppose he knows that freshmen skip 2% of their class

KIM [24]

Answer:

We conclude that seniors skip more than 2% of their classes at 0.01 level of significance.

Step-by-step explanation:

We are given that a professor wishes to discover if seniors skip more classes than freshmen. Suppose he knows that freshmen skip 2% of their classes.

He randomly samples a group of seniors and out of 2521 classes, the group skipped 77.

Let p = percentage of seniors who skip their classes.

So, Null Hypothesis, $H_0$ : p $\leq$ 2% {means that seniors skip less than or equal to 2% of their classes}

Alternate Hypothesis, $H_A$ : p > 2% {means that seniors skip more than 2% of their classes}

The test statistics that will be used here is One-sample z proportion statistics;

T.S. = $\frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of seniors who skipped their classes = $\frac{77}{2521}$

n = sample of classes = 2521

So, test statistics = $\frac{\frac{77}{2521} -0.02}{{\sqrt{\frac{\frac{77}{2521}(1-\frac{77}{2521})}{2521} } } } }$

= 3.08

The value of the test statistics is 3.08.

Now at 0.01 significance level, the z table gives critical value of 2.3263 for right-tailed test. Since our test statistics is more than the critical value of z as 2.3263 < 3.08, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that seniors skip more than 2% of their classes.

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3 years ago