sin 45 = opp/hyp
sin 45 = 4 / y
y = 4/sin 45
y = 4 /((sqrt2)/2)=4* sqrt(2)
tan 45 =opp/adj
tan 45 = 4/(x-3)
1 = 4/(x-3)
x-3 = 4
x=7
B
275,000 km
The moons A, B, C form a right triangle with AC forming a hypotenuse with the diameter of the planet and the distance of both moons from the surface. So add A to the surface, plus the diameter of the planet, plus surface to c.
115000+45000+115000 = 275000
This has both a horizontal and a vertical asymptote. There are no slant (oblique) asymptotes cuz the degree of the numerator is not higher than that of the denominator. If the degree of the numerator is less than the degree of the denominator, which is our case here, then the horizontal asymptote is 0. But we also have a vertical asymptote, which occurs where the denominator = 0. We all know that we break every rule known to mankind if we try to divide by 0, so there also a vertical asymptote at x = 2.
Answer: a. 0.61
b. 0.37
c. 0.63
Step-by-step explanation:
From the question,
P(A) = 0.39 and P(B) = 0.24
P(success) + P( failure) = 1
A) What is the probability that the component does not fail the test?
Since A is the event that the component fails a particular test, the probability that the component does not fail the test will be P(success). This will be:
= 1 - P(A)
= 1 - 0.39
= 0.61
B) What is the probability that a component works perfectly well (i.e., neither displays strain nor fails the test)?
This will be the probability that the component does not fail the test minus the event that the component displays strain but does not actually fail. This will be:
= [1 - P(A)] - P(B)
= 0.61 - 0.24
= 0.37
C) What is the probability that the component either fails or shows strain in the test?
This will simply be:
= 1 - P(probability that a component works perfectly well)
= 1 - 0.37
= 0.63
Answer:
NO, as per study, I cant see any other problem than the sample size in the procedure.
From the graph there is a slight quadratic relationship between temperature and number of O-rings.
As in the graph, we can see that above 50°F but below 55°F number of O-rings in 3 but after 55°F as temperature goes on increasing the number of O-rings decreases and remains constant up to 70°F and above 70°F the number of O-rings increases to 2. Hence, we can say that there is a relationship between temperature and number of O-rings.
If we want to fit a linear regression through these seven observations, the slope would be positive as linear regression line passes through the average.
Looking at the relationship, slope must be significantly different from zero as there is a relationship between two variables, where as slope significantly zero implies no relationship. However, we have only seven points so drawing a conclusion is difficult as the nature of the relationship is not clearly visualized by this graph.