Answer:
Given: BD is an altitude of △ABC .
Prove: sinA/a=sinC/c
Triangle ABC with an altitude BD where D is on side AC. Side AC is also labeled as small b. Side AB is also labeled as small c. Side BC is also labeled as small a. Altitude BD is labeled as small h.
Statement Reason
BD is an altitude of △ABC .
Given △ABD and △CBD are right triangles. (Definition of right triangle)
sinA=h/c and sinC=h/a
Cross multiplying, we have
csinA=h and asinC=h
(If a=b and a=c, then b=c)
csinA=asinC
csinA/ac=asinC/ac (Division Property of Equality)
sinA/a=sinC/c
This rule is known as the Sine Rule.
Answer:
C as C^unt
Step-by-step explanation:
Answer:
I hate that clfufjwwjdkfkrifjeidoqodjfrjkejakxkdk
Step-by-step explanation:
Answer:
-3x= 2×2-4
Step-by-step explanation:
-3x= 4-4
-3x= 0
divide both sides by the co-efficient of x
-3x/-3= 0÷-3
x = 0
Answer:
The answer is 0.13.
Step-by-step explanation:
The formula for speed is distance divided by time. 0.92 / 7 = 0.13.