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skad [1K]
4 years ago
5

HELP ME PLEASE

Mathematics
1 answer:
Gennadij [26K]4 years ago
8 0
Let P be the final value
Let r be the rate
Let t be the time in years
Let C be the initial value
Let n be the number of times interest is given per year

P = C (1 + r/n) ^ (nt)

r = 0.075 (7.5%)
t = 3/4 years
C = $1500
r = 4 (4 quarters in one year)

P = C (1+r/n)^ (t/n)
= 1500 * (1 + 0.075/4) ^ (3/4 * 4)
= 1585.97

Have an awesome day!

If you are wondering, a quarter means 1/4 of a year.
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If the product of two consecutive integers is decreased by 20 times the greater integer, the result is 442. find the integers
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Let the first integer be x.  Then the next consecutive integer is x+1.

Translating the word problem into symbols, x(x+1)-20(x+1) = 442.

Then x^2 + x - 20x - 20 = 442

or      x^2 - 19x - 462 = 0

Solve by completing the square:

          x^2 - 19x + 90.25 - 90.25 - 462 = 0

           (x-9.5)^2 - 552.25 = 0

Taking the positive square root of both sides, we get x-9.5 = 23.5, or
                                                                                    x        = 33

The two consecutive integers are 33 and 34.

Check:  (33)(34)-20(34) = 442 (as expected).

            
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What is the angle supplementary to the angle measuring 165°? A. 75° B. 195° C. 60° D. 15°
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Answer:

Step-by-step explanation:

Remark

I take it that 24 is in front of j which means that the term is 24j.  There shouldn't be a comma there.

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24j - 16 = 8(3j - 2)    That's the answer.

Answer: 8 (3j - 2)

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<em><u>Answer</u></em><em><u> </u></em><em><u>:</u></em><em><u>-</u></em><em><u> </u></em><em><u> </u></em><em><u>Opti</u></em><em><u>on</u></em><em><u> </u></em><em><u>B</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>co</u></em><em><u>rrect</u></em><em><u> </u></em><em><u>!</u></em><em><u>!</u></em>

x = 4

<em><u>Step</u></em><em><u> </u></em><em><u>by</u></em><em><u> </u></em><em><u>step</u></em><em><u> </u></em><em><u>explan</u></em><em><u>ation</u></em><em><u> </u></em><em><u>:</u></em><em><u>-</u></em><em><u> </u></em>

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